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3 years ago

Please help FAST:

Mathematics

1 answer:

Alex_Xolod [135]3 years ago

8 0

Answer:

car a, car b

Step-by-step explanation:

car a 2x + 2= 4x

car b 3x + 3= 9x

both cars 13x

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Find tan , sin , and seco, where 0 is the angle shown in the figure.

kicyunya [14]

Answer:

tan(θ) = 5/3
sin(θ) = 5√34/34
sec(θ) = √34/3

Step-by-step explanation:

The hypotenuse is given by the Pythagorean theorem:

h = √(3² +5²) = √34

The trig functions are the ratios of sides:

Tan = Opposite/Adjacent

tan(θ) = 5/3

Sin = Opposite/Hypotenuse

sin(θ) = 5/√34 = (5/34)√34

Sec = Hypotenuse/Adjacent

sec(θ) = √34/3

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4 years ago

What is cos(A)? please explain

Ipatiy [6.2K]

Answer:

cos(A) = adjacent side / hypotenuse

= 4/5

5 0

3 years ago

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What is the equation of the line that is parallel to the line 5x + 2Y=12 and passesthrough the point (-2,4) ?

sladkih [1.3K]

Answer:

y = $-\frac{5}{2}$ x - 1

Step-by-step explanation:

5x + 2y = 12

2y = -5x + 12

y = $-\frac{5}{2}$ x + 6

y = mx + b

4 = $-\frac{5}{2}$ ( -2 ) + b

4 = 5 + b

b = -1

y = $-\frac{5}{2}$ x - 1

5 0

3 years ago

What is the area of ABC?

Salsk061 [2.6K]

Answer:

Area of triangle ABC = 10

Option C is correct.

Step-by-step explanation:

We need to find area of triangle ABC

We are given A(2,1) B(4,7) and C(6,3)

The formula used to find $Area \ of \ triangle=\frac{1}{2}base\times height$ ABC is:

In the given triangle base= AC and height = BC

First we need to find the distance between A and C and B and C

The formula used to find distance between AC $Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

We have $x_1=2, y_1=1, x_2=6, y_2=3$

Putting values and finding distance

$Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\Distance=\sqrt{(6-2)^2+(3-1)^2}\\Distance=\sqrt{(4)^2+(2)^2}\\Distance=\sqrt{16+4}\\Distance=\sqrt{20}$

find distance between BC $Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

We have $x_1=4, y_1=7, x_2=6, y_2=3$

Putting values and finding distance

$Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\Distance=\sqrt{(6-4)^2+(3-7)^2}\\Distance=\sqrt{(2)^2+(4)^2}\\Distance=\sqrt{4+16}\\Distance=\sqrt{20}$

So, We have height = $\sqrt{20}$ and base = $\sqrt{20}$

Finding area of triangle

$Area \ of \ triangle=\frac{1}{2}base\times height\\Area \ of \ triangle=\frac{1}{2}\sqrt{20} \times \sqrt{20} \\Area \ of \ triangle=\frac{1}{2}\times 20\\Area \ of \ triangle=10$

So, Area of triangle ABC = 10

Option C is correct.

7 0

3 years ago

I don't like math it makes me sad

PSYCHO15rus [73]

It would be 250 in because you see 10x20 is 200 and and 10x10 is 100. But since part of the figure is a triangle you have to dive it by 2 and 100/2=50. 200+50=250
Hope that helps!

8 0

3 years ago

Read 2 more answers