Ask question

Ask question

All categories

3 years ago

12

A video game randomly chooses your car color and type. The probability of getting a red car is 0.25, and the probability of gett

ing a convertible is 0.40.Event A = You get a red car.Event B = You get a convertible.A and B are independent events if _____.

2 answers:

tangare [24]3 years ago

7 0

Answer:The probability of getting a red convertible is 0.10

Step-by-step explanation:

EleoNora [17]3 years ago

6 0

In probability 2 events are independent if the occurrence of 1 event does not affect the occurrence of the other event. Mathematically, if event A and event B are independent, then $P(A\&B)=P(A)\times P(B)$ . For our two events in this problem we have that $P(A)=0.25$ and $P(B)=0.40$ . If these two events are independent, then we should have that,

$P(A\&B)=P(A)\times P(B)\\P(A\times B)=0.25\times 0.4=0.1.$

.A and B are independent events if the probability of A and B is 0.1

You might be interested in

Plsss help me no links

Sindrei [870]

Answer:

D) 42.16

Total: $553.13

Step-by-step explanation:

Multiply the subtotal, 510.97, by 8.25%. To do that just turn the 8.25% into a decimal which is 0.0825. The answer to that would be 42.155025 and rounded it would be 42.16 so the tax would be $42.16.

The total to the entire thing would be $553.13 since you just add the tax and subtotal together.

8 0

3 years ago

Read 2 more answers

Grace is making holiday cards. Each rectangular card has an area of 28 square inches and the length is 3 inches more than the wi

melomori [17]

Length=7
Width =4
Area = length x width

3 0

3 years ago

The hypotenuse of a right triangle has endpoints A(4, 1) and B(–1, –2). On a coordinate plane, line A B has points (4, 1) and (n

GarryVolchara [31]

Answer:

$(-1,1),(4,-2)$

Step-by-step explanation:

Given: The hypotenuse of a right triangle has endpoints A(4, 1) and B(–1, –2).

To find: coordinates of vertex of the right angle

Solution:

Let C be point $(x,y)$

Distance between points $(x_1,y_1),(x_2,y_2)$ is given by $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$AC=\sqrt{(x-4)^2+(y-1)^2}\\BC=\sqrt{(x+1)^2+(y+2)^2}\\AB=\sqrt{(4+1)^2+(1+2)^2}=\sqrt{25+9}=\sqrt{34}$

ΔABC is a right angled triangle, suing Pythagoras theorem (square of hypotenuse is equal to sum of squares of base and perpendicular)

$34=\left [ (x-4)^2+(y-1)^2 \right ]+\left [ (x+1)^2+(y+2)^2 \right ]$

Put $(x,y)=(-1,1)$

$34=\left [ (-1-4)^2+(1-1)^2 \right ]+\left [ (-1+1)^2+(1+2)^2 \right ]\\34=25+9\\34=34$

which is true. So, $(-1,1)$ can be a vertex

Put $(x,y)=(4,-2)$

$34=\left [ (4-4)^2+(-2-1)^2 \right ]+\left [ (4+1)^2+(-2+2)^2 \right ]\\34=9+25\\34=34$

which is true. So, $(4,-2)$ can be a vertex

Put $(x,y)=(1,1)$

$34=\left [ (1-4)^2+(1-1)^2 \right ]+\left [ (1+1)^2+(1+2)^2 \right ]\\34=9+4+9\\34=22$

which is not true. So, $(1,1)$ cannot be a vertex

Put $(x,y)=(2,-2)$

$34=\left [ (2-4)^2+(-2-1)^2 \right ]+\left [ (2+1)^2+(-2+2)^2 \right ]\\34=4+9+9\\34=22$

which is not true. So, $(2,-2)$ cannot be a vertex

Put $(x,y)=(4,-1)$

$34=\left [ (4-4)^2+(-1-1)^2 \right ]+\left [ (4+1)^2+(-1+2)^2 \right ]\\34=4+25+1\\34=30$

which is not true. So, $(4,-1)$ cannot be a vertex

Put $(x,y)=(-1,4)$

$34=\left [ (-1-4)^2+(4-1)^2 \right ]+\left [ (-1+1)^2+(4+2)^2 \right ]\\34=25+9+36\\34=70$

which is not true. So, $(-1,4)$ cannot be a vertex

So, possible points for the vertex are $(-1,1),(4,-2)$

7 0

3 years ago

Read 2 more answers

which of the following are among the five basic postulates of euclidean geometry? check all that apply

MAVERICK [17]

The five essential hypothesizes of Geometry, additionally alluded to as Euclid's proposes are the accompanying:
1.) A straight line section can be drawn joining any two focuses.
2.) Any straight line portion can be expanded uncertainly in a straight line.
3.) Given any straight line fragment, a circle can be drawn having the portion as a span and one endpoint as the inside.
4.) All correct points are harmonious.
5.) If two lines are drawn which meet a third such that the total of the internal points on one side is under two right edges (or 180 degrees), then the two lines unavoidably should converge each other on that side if reached out sufficiently far.

7 0

3 years ago

Solve this problem<br> √-16

a_sh-v [17]

Answer:

$4i$

Step-by-step explanation:

$\sqrt{-1} = i$

Therefore $\sqrt{-16} = \sqrt{16} \sqrt{-1} \\=4i$

3 0

3 years ago