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Aliun [14]
4 years ago
7

Need help with this assignment please

Mathematics
2 answers:
zlopas [31]4 years ago
8 0

Answer:

-5a+3a+1

Step-by-step explanation:

Add all of them together, and you get your answer. Hope that this helps you and have a great day

LUCKY_DIMON [66]4 years ago
6 0
-5a+3a+1 do that and that’s your answer
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laiz [17]

Answer:

(a)  See below.

(b)  x = 0 or x = 1

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Step-by-step explanation:

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<u>Part (a)</u>

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\begin{aligned}\implies f(2) & =\dfrac{\ln |2-1|}{2}\\\\ & =\dfrac{\ln 1}{2}\\\\ & =\dfrac{0}{2}\\\\ & =0\end{aligned}

Therefore, as the function is defined at x = 2, the function is continuous at x = 2.

<u>Part (b)</u>

Given interval:  [-2, 2]

Logs of negative numbers or zero are undefined.  As the numerator is the natural log of an <u>absolute value</u>, the numerator is undefined when:

|x - 1| = 0 ⇒ x = 1.  

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So the function is discontinuous at x = 0 or x = 1 on the interval [-2, 2].

<u>Part (c)</u>

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\implies f(0)=\dfrac{\ln |0-1|}{0}=\dfrac{\ln 1}{0}=\dfrac{0}{0}

Therefore, there is a hole at x = 0.

The removable discontinuity of a function occurs at a point where the graph of a function has a hole in it.   Therefore, x = 0 is a removable discontinuity.

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