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kupik [55]
3 years ago
4

An asteroid is moving along a straight line. A force acts along the displacement of the asteroid and slows it down. The asteroid

has a mass of 3.5× 104 kg, and the force causes its speed to change from 6600 to 5700m/s. (a) What is the work done by the force? (b) If the asteroid slows down over a distance of 1.5× 106 m determine the magnitude of the force.

Physics
1 answer:
Lady_Fox [76]3 years ago
8 0

Try this option; answers are marked with red colour: a) 19.215 GJ; b) 12.81 kN.

All the details are in the attached picture.

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Sam runs 9 kilometers in 2.5 hours. what is his speed?
svp [43]

Considering the definition of speed, the speed of Sam is 3.6 \frac{km}{h}.

<h3>Definition of speed</h3>

Speed ​​is a quantity that expresses the relationship between the space traveled by an object. That is, the speed is associated with the change of position of an object in space within a certain amount of time.

The speed can be calculated using the expression:

speed= \frac{displacement}{time}

<h3>Speed of Sam</h3>

In this case, you know:

  • displacement= 9 km
  • time= 2.5 h

Replacing in the definition of speed:

speed= \frac{9 km}{2.5 h}

Solving:

<u><em>speed= 3.6 </em></u>\frac{km}{h}

Finally, the speed of Sam is 3.6 \frac{km}{h}.

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3 0
2 years ago
Ishmael has an object that produces an electric field. He then places another charged object inside that electric field.
taurus [48]

The increase the magnitude of the electric force ;

1) The charges on the objects must be increased

2) The distance of separation between the objects must be reduced.

<h3>What is electric field?</h3>

The term electric field has to do with the region where the electric force on an object is expirieced. We must the note thate electric force is a result of the influence of a charge on another.

The increase the magnitude of the electric force ;

1) The charges on the objects must be increased

2) The distance of separation between the objects must be reduced.

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3 0
2 years ago
A car of mass 1600 kg traveling at 27.0 m/s is at the foot of a hill that rises vertically 135 m after travelling a distance of
Zarrin [17]

Answer:

Neglecting any frictional losses, the average power delivered by the car's engine is 10565 W

Explanation:

The energy conservation law indicates that the energy must be the same at the bottom of the hill and at the top of the hill.  

The energy at the bottom is only the Kinect energy (K_1) of the car in motion, but in the top, the energy is the sum of its Kinect energy (K_2), potential energy (P) and the work (W) done by the engine.

K_1 = K_2 + P + W

then, the work done by the engine is:

W = K_1 - K_2 - P

The formulas for the Kinetic and potential energy are:  

K=\frac{1}{2}mV^2\\P=mgh

where, m is the mass of the car, V the velocity, g the gravity and h is the elevation of the hill.

Using the formulas:

W=\frac{1}{2}mV_1^2-\frac{1}{2}mV_2^2-mgh

Replacing the values:

W=\frac{1}{2}(1600Kg)(27m/s)^2-\frac{1}{2}(1600Kg)(14m/s)^2-(1600Kg)(9.8m/s^2)(135m)\\W=-1690400 J

The negative of this value indicates the direction of the work done, but for the problem, you only care about the magnitude, so the power is W=1690400 J. Now, the power is equal to work/time so you need to find the time the car took to get to the top of the hill.

The average speed of the car is (27+14)/2=20m/s, and t=d/v so the time is:

t=\frac{3200m}{20m/s}=160s

the power delivered by the car's engine was:

power=\frac{work}{time}=\frac{1690400J}{160s}=10565W

8 0
4 years ago
A rectangular gasoline tank can hold 50.0 kg of gasoline when full. What is the depth of the tank if it is 0.500-m wide by 0.900
sweet-ann [11.9K]

Answer:

0.16 m

Explanation:

A rectangular gasoline tank can hold 50.0 kg of gasoline when full, and the density of gasoline is 6.8 × 10² kg/m³. We can find the volume occupied by the gasoline (volume of the tank).

50.0 kg × (1 m³/6.8 × 10² kg) = 0.074 m³

The volume of the rectangular tank is:

volume = width × length × depth

depth = volume / width × length

depth = 0.074 m³ / 0.500 m × 0.900 m

depth = 0.16 m

3 0
3 years ago
Which sediments typically make up the C horizon?
Nastasia [14]
B) sand, silt, and clay!
5 0
4 years ago
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