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saw5 [17]
3 years ago
8

provide two questions from imagine math, the answers, and how you solved them. WILL MARK AS BRAINLIEST!!!! don't report this que

stion its not personal its for my algebra class. THANKS!!!
Mathematics
1 answer:
ozzi3 years ago
5 0

Answer:

im in 4th grade on my brothers pc so these answers are small its 43x14=602 and 654 divided by 6=109

Step-by-step explanation:

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Tems11 [23]
<span>1/3(21-3a)=6-a
I simplified the equation to the form, which is simple to understand
<span>1/3(21-3a)=6-a
Simplifying:
<span> + 0.333333333333*(21-3a)=6-a
Reorder the terms in parentheses
<span>+(+7-1a)=6-a
Remove unnecessary parentheses
<span>+7-1a=+6-a
We move all terms containing a to the left and all other terms to the right.
<span>-1a+1a=+6-7
We simplify left and right side of the equation.
<span>a=-1
<span>0=-1
The left and right sides are not equal, therefore there is no solution. This equation is invalid
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3 0
3 years ago
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Which of the following is NOT a topic that you will learn about with matrices in this lesson? Addition Multiplication Interpreta
KatRina [158]
Addition

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6 0
2 years ago
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ASAP PLEASE please please
Aleksandr [31]

{ \qquad\qquad\huge\underline{{\sf Answer}}}

Let's solve ~

\qquad \sf  \dashrightarrow \:  \cfrac{1}{b}  + 10 =  \cfrac{9}{b}  + 7

\qquad \sf  \dashrightarrow \:  \cfrac{9}{b}  -   \cfrac{1}{b} =  10 -   7

\qquad \sf  \dashrightarrow \:  \cfrac{8}{b}   =  3

\qquad \sf  \dashrightarrow \: b =  \cfrac{8}{3}

5 0
2 years ago
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sveticcg [70]

Answer:

The required expression is \frac{y}{4}-3.

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Step-by-step explanation:

Consider the provided phase.

3 less than the quotient of a number y and 4

The quotient of a number y and 4 can be written as: \frac{y}{4}

Now 3 less than the quotient of a number y and 4  can be written as:

\frac{y}{4}-3

Hence, the required expression is \frac{y}{4}-3.

Now evaluate when y=20.

Substitute y=20 in above expression.

\frac{20}{4}-3

5-3

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Hence, the value of the expression when y=20 is 2.

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3 years ago
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baherus [9]

Answer:

I will do it but what is the GCF of part B

Step-by-step explanation:

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