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Lunna [17]
3 years ago
8

What is the name of the relationship between 1 and 4?

Mathematics
2 answers:
Nesterboy [21]3 years ago
4 0
D adjacent angle is the answer
Zanzabum3 years ago
3 0
< 1 and < 4 are alternate interior angles
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Write an equation of a line in slope-intercept form given slope= 6 and passes through the point (-3,7).
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Use formula y = mx+ b  Y is your point y in the pair: 7 M is slope : 6 X is your x in the pairs : -3   7 = 6 (-3) + b 7 = -18 + b 7+ 18 = b  25= b   So , it will be  Y= 6x + 25

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Which equation represents a proportional relationship? A y=x+13y=x+\frac{1}{3}y=x+ 3 1 ​ B y=1−13xy=1-\frac{1}{3}xy=1− 3 1 ​ x C
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Sketch graph of the function
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2 years ago
WRITE DOWN THE FALUE OF 7
Maru [420]

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(I need to know where the seven is located/placed.) Please give a clear answer or attach a photo next time so everybody who sees your question will understand.

Step-by-step explanation:

Comparing the numbers 700, 70, and 7; the digit "7" has a different value depending on its place within the number.

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8 0
3 years ago
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Solve for x, 0 ≤ x ≤2π (2cosx-1)(2sinx+√3 ) = 0
vladimir1956 [14]

Answer:

x = π/3, x = 5π/3, x = 4π/3

Step-by-step explanation:

Let's split the given equation (2cosx-1)(2sinx+√3 ) = 0 into two parts, and solve each separately. These parts would be 2cos(x) - 1 = 0, and 2sin(x) + √3  = 0.

2\cos \left(x\right)-1=0,\\2\cos \left(x\right)=1,\\\cos \left(x\right)=\frac{1}{2}

Remember that the general solutions for cos(x) = 1/2 are x = π/3 + 2πn and x = 5π/3 + 2πn. In this case we are given the interval 0 ≤ x ≤2π, and therefore x = π/3, and x = 5π/3.

Similarly:

\:2\sin \left(x\right)+\sqrt{3}=0,\\2\sin \left(x\right)=-\sqrt{3},\\\sin \left(x\right)=-\frac{\sqrt{3}}{2}

The general solutions for sin(x) = - √3/2 are x = 4π/3 + 2πn and x = 5π/3 + 2πn. Therefore x = 4π/3 and x = 5π/3 in this case.

So we have x = π/3, x = 5π/3, and x = 4π/3 as our solutions.

5 0
3 years ago
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