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Lunna [17]
3 years ago
8

What is the name of the relationship between 1 and 4?

Mathematics
2 answers:
Nesterboy [21]3 years ago
4 0
D adjacent angle is the answer
Zanzabum3 years ago
3 0
< 1 and < 4 are alternate interior angles
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Standard Error from a Formula and a Bootstrap Distribution Sample A has a count of 30 successes with and Sample B has a count of
tia_tia [17]

Answer:

Using a formula, the standard error is: 0.052

Using bootstrap, the standard error is: 0.050

Comparison:

The calculated standard error using the formula is greater than the standard error using bootstrap

Step-by-step explanation:

Given

Sample A                          Sample B

x_A = 30                              x_B = 50

n_A = 100                             n_B =250

Solving (a): Standard error using formula

First, calculate the proportion of A

p_A = \frac{x_A}{n_A}

p_A = \frac{30}{100}

p_A = 0.30

The proportion of B

p_B = \frac{x_B}{n_B}

p_B = \frac{50}{250}

p_B = 0.20

The standard error is:

SE_{p_A-p_B} = \sqrt{\frac{p_A * (1 - p_A)}{n_A} + \frac{p_A * (1 - p_B)}{n_B}}

SE_{p_A-p_B} = \sqrt{\frac{0.30 * (1 - 0.30)}{100} + \frac{0.20* (1 - 0.20)}{250}}

SE_{p_A-p_B} = \sqrt{\frac{0.30 * 0.70}{100} + \frac{0.20* 0.80}{250}}

SE_{p_A-p_B} = \sqrt{\frac{0.21}{100} + \frac{0.16}{250}}

SE_{p_A-p_B} = \sqrt{0.0021+ 0.00064}

SE_{p_A-p_B} = \sqrt{0.00274}

SE_{p_A-p_B} = 0.052

Solving (a): Standard error using bootstrapping.

Following the below steps.

  • Open Statkey
  • Under Randomization Hypothesis Tests, select Test for Difference in Proportions
  • Click on Edit data, enter the appropriate data
  • Click on ok to generate samples
  • Click on Generate 1000 samples ---- <em>see attachment for the generated data</em>

From the randomization sample, we have:

Sample A                          Sample B

x_A = 23                              x_B = 57

n_A = 100                             n_B =250

p_A = 0.230                          p_A = 0.228

So, we have:

SE_{p_A-p_B} = \sqrt{\frac{p_A * (1 - p_A)}{n_A} + \frac{p_A * (1 - p_B)}{n_B}}

SE_{p_A-p_B} = \sqrt{\frac{0.23 * (1 - 0.23)}{100} + \frac{0.228* (1 - 0.228)}{250}}

SE_{p_A-p_B} = \sqrt{\frac{0.1771}{100} + \frac{0.176016}{250}}

SE_{p_A-p_B} = \sqrt{0.001771 + 0.000704064}

SE_{p_A-p_B} = \sqrt{0.002475064}

SE_{p_A-p_B} = 0.050

5 0
2 years ago
A car dealership decreased the price of a certain car by 13%. The original price was $45,400.
ira [324]

Answer:

5902

Step-by-step explanation:

Solution: 13% off 45400 is equal to (13 x 13) / 100 = 5902.

5 0
3 years ago
What is the numerator when 0.83 is written as a fraction with a denominator of 100
kifflom [539]
0.83 can also be written as 83/100, so the numerator will be 83.
4 0
2 years ago
Using the scale of 5 cm: 25 m, find the actual length of the parking lot. Be sure to include units.
k0ka [10]

Answer:

25 m = 25 × 100 = 2500 cm

5 ÷ 5 = 1

2500 ÷ 5 = 500

5:2500 ratio simplified is 1:500

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Given h(x)=-x-4, solve for x when h(x)=4
Brilliant_brown [7]

Step-by-step explanation:

h(x)=-x-4

but h(x)=4

4=-x-4

x=-4-4

x=-8

5 0
3 years ago
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