Given A={1,2,3}, B={2,4,6} and C={1,2,3,4,5,6}, then A ∩ (B ∩ C) =
oksian1 [2.3K]
Answer:
Step-by-step explanation:
A={1,2,3}
B={2,4,6}
C={1,2,3,4,5,6}
B∩C={2,4,6}
A∩(B∩C)={1,2,3}∩{2,4,6}={2}
Answer: 4
Step-by-step explanation: To have an equation with no solution you have to get something like 0=1 meaning you have to remove all the variables. In this equation you would distribute to get xy+2y+2x=2x+12+4x where y is the missing number. then combining like terms you get xy+2x+2y=6x+12. Subtracting 2x from both sides you get xy+2y=4x+12. Now to get the variables gone y has to be 4 so that the variables to cancel out. By plugging in 4 you can see this works; 4x+8=4x+12 and by subtracting 4x from both sides you get 8=12 which is not true meaning there is no solution.
Letting
, we get
and
, so we can parameterize the intersection by
where
.
Image attached.
The correct answer is, obviously, 34/7.
