Answer:
Step-by-step explanation:
To find the quotient, we first need to know what quotient means.
Quotient is the solution to division problems.
So here is how we have to do this, first we identify our fractions:
Next, we must turn the fraction we are dividing by into a reciprocate:
Now we have 
Next, we multiply!:
Simplified:
Answer:
x = 53.6588°
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
<u>Trigonometry</u>
- [Right Triangles Only] SOHCAHTOA
- [Right Triangles Only] cos∅ = adjacent over hypotenuse
Step-by-step explanation:
<u>Step 1: Define</u>
We are given a right triangle. We can use trig to find the missing angle.
<u>Step 2: Identify Variables</u>
<em>POV from angle x</em>
Angle = <em>x</em>
Adjacent = 16
Hypotenuse = 27
<u>Step 3: Solve for </u><em><u>x</u></em>
- Substitute: cosx° = 16/27
- Inverse: x° = cos⁻¹(16/27)
- Evaluate: x = 53.6588°
We have
3 / (x-5) - x/5
We make the GCF and we have
15/[ 5(x-5) ] - x(x-5)/[ 5(x-5)]
= [ 15 - x(x-5) ] [5(x-5)]
= [ 15 - x^2 + 5x] / [ 5 (x-5) ]
= [15 - x^2 + 5x]/[5x - 25]
An answer to your question is (15-x^2+5x)/(5x-25)
Answer:
A
Step-by-step explanation:
The first thing you need to do is find the slope. Find two perfect points.
In this case I chose (0,0) and (4,1). Slope is basically rise over run. In other words, how much you go up, and how much you go right. We rise up one and to the right 4.
Question 1: C. (-4, 8]
With B, I think you assumed since there are two separate lines for the function, there must be two separate ranges. Additionally, you state that the left one has a range from -4 to 3, each non-inclusive, which is incorrect as there is a solid point at y = 3. However, the -4 non-inclusive part is correct.
Basically, this is all one function therefore there should be a single range. Since as you can see on the graph, 8 is included, the new range should be (-4, 8]. The function extends from -4, non-inclusive, to 8, inclusive. Even though there is a gap between the two parts, it is a singular function and as a whole, both are considered when calculating the range.
Question 2: C, {x | x > 10}
You are correct! x = 10 is a vertical asymptote for this function - the function will never reach this value so you should not use the "greater than or equal to" sign.
