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masha68 [24]
3 years ago
6

Assume that when you take a​ bath, you fill a tub to the halfway point. The tub measures 5 feet by 3 feet by 2.8 feet. When you

take a​ shower, you use a shower head with a flow rate of 1.52 gallons per​ minute, and you typically spend 12 minutes in the shower. There are 7.5 gallons in one cubic foot.
Mathematics
1 answer:
Irina18 [472]3 years ago
4 0
Total water used while taking a bath is half the volume of water in tub.
Volume of water used=(volume)/2
=(5×3×2.8)/2
=42/2
=21 cubic feet

Total amount of water used while taking a shower will be given by:
Total amount of water=rate×time
=1.52×12
=18.24 gallons
Thus amount of water in cubic feet if there are 7.5 gallons in 1 cubic foot will be:
amount=18.24/7.5=2.432 cubic feet.

Therefore the conclusion is, the person is using more water in bathing than shower.
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Answer:

x = 58

Step-by-step explanation:

The exterior angle is equal to the sum of the opposite interior angles

90  = 32+x

Subtract 32 from each side

90-32 = x

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3 years ago
The plane x + y + z = 12 intersects paraboloid z = x^2 + y^2 in an ellipse.(a) Find the highest and the lowest points on the ell
emmasim [6.3K]

Answer:

a)

Highest (-3,-3)

Lowest (2,2)

b)

Farthest (-3,-3)

Closest (2,2)

Step-by-step explanation:

To solve this problem we will be using Lagrange multipliers.

a)

Let us find out first the restriction, which is the projection of the intersection on the XY-plane.

From x+y+z=12 we get z=12-x-y and replace this in the equation of the paraboloid:

\bf 12-x-y=x^2+y^2\Rightarrow x^2+y^2+x+y=12

completing the squares:

\bf x^2+y^2+x+y=12\Rightarrow (x+1/2)^2-1/4+(y+1/2)^2-1/4=12\Rightarrow\\\\\Rightarrow (x+1/2)^2+(y+1/2)^2=12+1/2\Rightarrow (x+1/2)^2+(y+1/2)^2=25/2

and we want the maximum and minimum of the paraboloid when (x,y) varies on the circumference we just found. That is, we want the maximum and minimum of  

\bf f(x,y)=x^2+y^2

subject to the constraint

\bf g(x,y)=(x+1/2)^2+(y+1/2)^2-25/2=0

Now we have

\bf \nabla f=(\displaystyle\frac{\partial f}{\partial x},\displaystyle\frac{\partial f}{\partial y})=(2x,2y)\\\\\nabla g=(\displaystyle\frac{\partial g}{\partial x},\displaystyle\frac{\partial g}{\partial y})=(2x+1,2y+1)

Let \bf \lambda be the Lagrange multiplier.

The maximum and minimum must occur at points where

\bf \nabla f=\lambda\nabla g

that is,

\bf (2x,2y)=\lambda(2x+1,2y+1)\Rightarrow 2x=\lambda (2x+1)\;,2y=\lambda (2y+1)

we can assume (x,y)≠ (-1/2, -1/2) since that point is not in the restriction, so

\bf \lambda=\displaystyle\frac{2x}{(2x+1)} \;,\lambda=\displaystyle\frac{2y}{(2y+1)}\Rightarrow \displaystyle\frac{2x}{(2x+1)}=\displaystyle\frac{2y}{(2y+1)}\Rightarrow\\\\\Rightarrow 2x(2y+1)=2y(2x+1)\Rightarrow 4xy+2x=4xy+2y\Rightarrow\\\\\Rightarrow x=y

Replacing in the constraint

\bf (x+1/2)^2+(x+1/2)^2-25/2=0\Rightarrow (x+1/2)^2=25/4\Rightarrow\\\\\Rightarrow |x+1/2|=5/2

from this we get

<em>x=-1/2 + 5/2 = 2 or x = -1/2 - 5/2 = -3 </em>

<em> </em>

and the candidates for maximum and minimum are (2,2) and (-3,-3).

Replacing these values in f, we see that

f(-3,-3) = 9+9 = 18 is the maximum and

f(2,2) = 4+4 = 8 is the minimum

b)

Since the square of the distance from any given point (x,y) on the paraboloid to (0,0) is f(x,y) itself, the maximum and minimum of the distance are reached at the points we just found.

We have then,

(-3,-3) is the farthest from the origin

(2,2) is the closest to the origin.

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3 years ago
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Answer:

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Step-by-step explanation:

we know that

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plus the perimeter of a square minus the diameter of the circle

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P=\pi r+4(b)-D

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b=16\ cm

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substitute

P=(3.14)(8)+4(16)-16

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Answer:

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Step-by-step explanation:

Using AC method:

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Here, a = 4, b = -27, and c = 18.

ac = 4 × 18 = 72

Factors of 72 that add up to -27: -3 and -24

Divide factors by a: -3/4 and -24/4

Reduce: -3/4 and -6/1

So the factored expression is:

(4t − 3) (t − 6)

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