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AysviL [449]
3 years ago
13

The intersection of any two disjoint sets is a null set. Justify your answer.​

Mathematics
1 answer:
Ne4ueva [31]3 years ago
8 0

Answer:

Yes The intersection of any two disjoint sets is a null set

if two sets do not have any common element  then their intersection does not have any element Therefore its intersection is a null set

Step-by-step explanation:

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This equation shows how the cost of a charity gala depends on the number of attendees. d = 5.1a + 11.6 The variable a represents
aleksandr82 [10.1K]

$98.30=5.1a+11.6
98.30-11.6=5a+11.6-11.6
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5 0
3 years ago
Use inductive reasoning to find the next term in this sequence 2,3,5,9,17. Then explain the rule for the pattern.
NISA [10]

We have been given the sequence 2,3,5,9,17.

We can write the terms of this sequence as

2=2^0+1\\
3=2^1+1\\
5=2^2+1\\
9=2^3+1\\
17=2^4+1\\

From the above term we can see that for the first term we take exponent 0 on 2 and then add 1 .

For second term we take exponent 1 on 2 and then add 1 .

For third term we take exponent 2 on 2 and then add 1 .

Using this fact for the next term of the sequence i.e. 6th term, we can take exponent 5 on 2 and then add 1 .

Therefore, next term of the sequence is given by

2^5+1\\
=32+1\\
=33

Therefore, the next term is 33.

Using the above facts, the pattern is given by

a_n=2^{n-1}+1

7 0
3 years ago
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ELEN [110]

Answer:

The answer is C.  11/29

Step-by-step explanation:

Simplify the left side.

29a - 5 = 6

Move all terms not containing  a  to the right side of the equation.

29a = 11

Divide each term by  29  and simplify.

a =  11 /29

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3 years ago
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omeli [17]
H = 6 in

V=bh

H=v/b

H=36/6

H=6
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3 years ago
Dylan owes half as much money as he used to owe. If he used to owe $28, which of the following expressions would reflect how muc
IrinaVladis [17]

Answer:

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Step-by-step explanation:

8 0
3 years ago
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