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3 years ago

Please Help me i'm timed

Mathematics

2 answers:

victus00 [196]3 years ago

7 0

Answer:

X=28

Step-by-step explanation:

4x+248=360

112=4x

x=28

Snowcat [4.5K]3 years ago

3 0

Answer:

Step-by-step explanation:

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What are the solutions to the inequality (4x-3)(2x-1) greater than or equal to 0

Fynjy0 [20]

Answer:

3/4 and 1/2

Step-by-step explanation:

(4x-3)(2x-1) ≥ 0

If the product of 2 numbers is zero, the one of the numbers must be equal to zero.

(4x-3)(2x-1) ≥ 0

(4x-3) ≥ 0 or (2x-1) ≥ 0

4x ≥ 0+3 2x ≥ 0+1

4x ≥ 3 2x ≥ 1

x ≥ 3/4 x ≥ 1/2

6 0

3 years ago

Read 2 more answers

What is the difference between 2/3 - 1/2

jok3333 [9.3K]

It is 1/6. Download photo math for only equations like this.

7 0

3 years ago

Please help asap !!!!!

Natasha2012 [34]

Answer:

<em>XY = 92 units</em>

Step-by-step explanation:

<u>Similar Shapes</u>

Two shapes are similar if all their corresponding side measures are in the same proportion.

The triangles UVW and YVX are similar because their side lengths are in the proportion 1:2, given the tick marks provided in the drawing.

This means that the measure of VX is twice the measure of VW,

The measure of YV is twice the measure of UV

The measure of XY is twice the measure of UW

This last proportion gives the equation:

z + 46 = 2z

Solving for z:

z = 46

Thus, XY = z+46 = 92

XY = 92 units

6 0

3 years ago

What is the area of this figure?

Alborosie

Answer:

146

Step-by-step explanation:

Hey there to find the area of this shape we will divide it into 2 shapes first one is a trapezoid and the second one is a triangle. first, we find the area of a trapezoid. to find the area of a trapezoid we use the formula:

A = $\frac{a+b}{2} * h$

in this situation

a = 4

b = 14

h = 10

Now we plug it into the formula which will look like:

A = $\frac{4+14}{2}*10$

if we solve it:

4+14 = 18

18/2 = 9

9*10 = 90

so the area of the trapezoid is 90

Now we find the area of triangle. to find the area of a triangle we use the formula:

A = $\frac{1}{2} * b * h$

in this situation

b = 14

h = 8 ( because the height of the trapezoid was 10 and the height of both shapes combined is 18 so we do 18 - 10 = 8 )

Now we put the numbers into the formula which will look like:

A = $\frac{1}{2}*14*8$

if we solve it :

14*8 = 112

$112*\frac{1}{2}$ = 56

so the area of the triangle is 56

Now we add the area of both shapes:

56 + 90 = 146

area of the big shape = 146

Have a wonderful day

7 0

3 years ago

Read 2 more answers

The vector wequalsaiplusbj is perpendicular to the line axplusbyequalsc and parallel to the line bxminusayequalsc. It is also tr

Likurg_2 [28]

Answer:

$\theta=45^{\circ}$

Step-by-step explanation:

We are given that the equation of lines

$x+\sqrt 3y=1$

$(1-\sqrt 3)x+(1+\sqrt 3)y=8$

According to question

The vector perpendicular to the lines is given by

$i+\sqrt 3j$ and $(1-\sqrt 3)i+(1+\sqrt 3)j$

Therefore, the angle between two vectors is given by

$cos\theta=\frac{a_1a_2+b_1b_2}{\sqrt{a^2_1+b^2_1}\sqrt{a^2_2+b^2_2}}$

Using the formula

$cos\theta=\frac{1(1-\sqrt 3)+\sqrt 3(1+\sqrt 3)}{2\times 2\sqrt 2}$

$cos\theta=\frac{1-\sqrt 3+\sqrt 3+3}{4\sqrt 2}=\frac{1}{\sqrt 2}$

$cos\theta=cos 45^{\circ}$

$\theta=45^{\circ}$

Hence, the acute angle between the lines is given by

$\theta=45^{\circ}$

3 0

3 years ago