All categories

2 years ago

Express the fractions 1/2, 3/16, and 7/8 with an LCD

1 answer:

6 0

You first need to find the LCD (lowest common denominator). You will need to find the smallest number that is a multiple of all numbers that is the denominator (2, 16, 8). Or, to say it another way, all the numbers in the denominator need to be a factor of this number.

You can find this by first checking if the largest number that is the denominator-- in this case 16-- is already the LCD, which means 16 is divisible by all the other numbers.

If this does not work, then multiply all the numbers together to get the LCD-- since you multiplied them together, you know that they will all be factors of the product.

However, you will be able to see that 16 is indeed the lowest common denominator:

2 × 8=16

8 × 2=16

16 × 1=16

So, after you find the LCD, multiply both the numerator and the denominator by the number that you would need to multiply the denominator to get the LCD (the whole point is that you want to get the denominator to be the LCD, but to do that you need to multiply both the top and bottom by the same number to keep the fraction the same).

(1/2) x (8/8)= 8/16

(3/16) x (1/1)= 3/16

(7/8) x (2/2)= 14/16

You might be interested in

MN is a diameter of a circle with centre ' O ' . If BD = CD , prove that ∠OAD = ∠OCD

Varvara68 [4.7K]

Answer:

$\sf \: Proved \: \angle \: OAD \: = \angle \: OCD$

Step-by-step explanation:

<em>Given:</em>

Mn is diameter of circle having centre O

and BD = OD,

<em><u>To prove that:</u></em>

<u> $\angle \: OAD \: = \angle \: OCD$ </u>

<em>Solution:</em>

Join the points O and B and draw OB,

On joining the line,

in ∆OCD and ∆OBD,

OC =OB → (Radius of same circle)

BD =CD → (from given)

OD =OD → (Common side in both the triangles)

Hence ∆OCD and ∆OBD are congruent from SSS property.

so we can say that,

$\angle \: OBD \: = \angle \: OCD$

Consider above prove as statement A

Corresponding angles of congruent traingle.

in ∆ OAB,

OA = OB (radius of same circle)

hence ∆OAB is an isosceles traingle.

We know that opposite angle of isosceles traingle are always equal. hence,

$\angle \: OBD \: = \angle \: OAB \\ \angle \: OAB \: = \angle \: OAD (same \: angles) \\ \angle \: OBD \: = \angle \: OAD$

Consider above prove as statement B

From Statement A & B we can say that

$\angle \: OAD \: = \angle \: OCD$

<em>Thanks for joining brainly community!</em>

5 0

1 year ago

A plane travels 600 miles in 3 hours. at this rate how far could the jet fly in 10 hours? math

IgorLugansk [536]

First you would have to find the distance it's going per hour.
$600 \div 3$
You will then get the answer of 200 m/hr. You can then plug in 200 m/hr to find how far the jet could fly in 10 hours
$200 \times 10$
You're final answer should be 2,000 miles

5 0

2 years ago

What is the formula for the Pythagorean theory?

harina [27]

A^2 + b^2= c^2
(a,b,c are right triangle sides)

3 0

2 years ago

Two angles of a triangle measure 22 and 53 what is the measure of the third angle

Musya8 [376]

The third angle is 105.
How do I know this?
Add 22 and 53:
22 + 53 = 75
All interior angles on a triangle should add up to 180.
Subtract 75 from 180:
180 - 75 = 105
105 is our answer.
Hope this helps! =)

3 0

2 years ago

Which piece of additional information can be used to prove △CEA ~ △CDB?

8_murik_8 [283]

<h3>Answer:</h3>

∠BDC and ∠AED are right angles

<h3>Step-by-step explanation:</h3>

Because ∠C ≅ ∠C, the additional bit of information above can be used to show AA similarity.

____

None of the other offered choices says anything about <em>both</em> triangles. In order to show similarity, you need information about corresponding parts of the <em>two</em> triangles. Information about one triangle alone is not sufficient.

5 0

2 years ago