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2 years ago

Mercury(II) oxide (HgO) decomposes to form mercury (Hg) and oxygen (O2). The balanced chemical equation is shown below.

Chemistry

2 answers:

Andreas93 [3]2 years ago

8 0

Answer:

15.63 moles of HgO are needed to produce 250.0 g of $O_{2}$

Explanation:

According to given balanced equation, 1 mole of $O_{2}$ is produced from 2 moles of HgO.

Number of moles $=\frac{mass}{molar mass}$

So 250 g of $O_{2}$ $=\frac{250}{32}moles O_{2}$

So moles of HgO needed $=2\times \frac{250}{32}moles HgO$

$=15.63 moles HgO$

____ [38]2 years ago

5 0

The answer to the question is C. 15.63

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Answer:

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Zinc sulfate is a 2-ion electrolyte,

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Answer: The value of i is 1.4 and 40% dissociation of 100 particles of zinc sulfate will yield 60 undissociated particles.

Explanation:

The equation used to calculate the Vant' Hoff factor in dissociation follows:

$\alpha =\frac{i-1}{n-1}$

where,

$\alpha$ = degree of dissociation = 40% = 0.40

i = Vant' Hoff factor

n = number of ions dissociated = 2

Putting values in above equation, we get:

$0.40=\frac{i-1}{2-1}\\\\0.40=i-1\\\\i=1.4$

The equation used to calculate the degee of dissociation follows:

$\alpha =\frac{\text{Number of particles dissociated}}{\text{Total number of particles taken}}$

Total number of particles taken = 100

Degree of dissociation = 40% = 0.40

Putting values in above equation, we get:

$0.40=\frac{\text{Number of particles dissociated}}{100}\\\\\text{Number of particles dissociated}=(0.40\times 100)=40$

This means that 40 particles are dissociated and 60 particles remain undissociated in the solution.

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Answer:

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