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evablogger [386]
3 years ago
10

In the following reaction, how many grams of ammonia (NH3) will react with 27.8 grams of nitric oxide (NO)? 4NH3 + 6NO → 5N2 + 6

H2O The molar mass of ammonia is 17.0337 grams and that of nitric oxide is 30.01 grams.
a- 23.7 grams

b- 10.5 grams

c- 73.5 grams

d- 32.7 grams
Chemistry
2 answers:
nasty-shy [4]3 years ago
8 0
The anwser is b10.5g
Rzqust [24]3 years ago
3 0
<span>4NH</span>₃<span> + 6NO → 5N</span>₂<span> + 6H</span>₂<span>O

mol of NO  =  </span>\frac{mass of NO}{Molar Mass of NO}
 
                  =  \frac{27.8 g}{30.01 g / mol}
                   
                  =  0.93 mol

Based on the balance equation mole ratio of NH₃  :  NO  is   4 : 6
                                                                                            =  2 : 3

If mol  of NO  =  0.93 mol

then mol of NH₃ = \frac{0.93 mol  *  2}{3}
                           
                          =  0.62 mol

Mass of ammonia =  mol  ×  molar mass
          
                             =  0.62 mol   ×  17.03 g/mol
 
                             =  10.54 g

Therefore B is the best answer





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Calculemos la formula empirica y molecular de carbonato de hierro Fe2(co3)3.Fe.38.3%C.12.3%.0.4 92% masa 292g
DENIUS [597]

Respuesta:

292 g / mol;

Por favor, consulte la explicación.

Explicación:

El número de átomos de cada elemento en el compuesto: Fe2 (co3) 3.

Fe = 2; C = 3; 0 = 3 * 3 = 9

Fe2 = 112 g / mol

C = 12 g / mol

O = 16 g /

Masa molecular = ((112 + (12 * 3) + (16 * 9)

= (112 + 36 + 144)

= 292 g / mol.

Total = 2 + 3 + 9 = 14

Fe2 = 112/292 * 100% = 38,356%

C = 36/292 * 100% = 12,328 * '

O = (16 * 9) / 292 * 100% = 49,32%

7 0
3 years ago
Universal indicator solution
Lynna [10]
Shred red cabbage ~ (3/4 of a very small head)

Put the cabbage pieces in a small container ~ ( you can use a Pyrex-4-cup measure, a bowl or even a plastic zipper bag)

Cover the cabbage with very hot water. Let it sleep until the water has cooled. (somewhere between lukewarm and room-temperature) 

The purple liquid you've made is your indicator. 
Pour it into a container and compost the cabbage.

Now look for substances that may be acids or bases. 
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You can also use solids around for baking are good too. (such as baking soda, salt, sugar, cream of tartar...)

Get containers for mixing (such as tea cups, because they are small, shallow and white inside)

Pour the indicator into the tea cups and add an acid or base.

Lemon juice, rice wine vinegar, and apple cider vinegar, turn the cabbage-water indicator into a pink.

Orange juice or fresh oranges (same thing) turn the cabbage-water indicator into an orangish-pinkish color. 

Baking soda turns the cabbage-water indicator blue.

Milk (non-fat) turns the cabbage-water indicator turn opaque and milky, yet purple.

An egg white (which won't get into the solution immediately until after a lot of stirring) turns the cabbage-water indicator blue.

Hint:
Bases mostly turn the indicator towards blue-ish colors such as purple, light blue, dark blue, opaque blue...

Acids mostly turn the indicator towards pink-ish colours such as orange-ish pink, floral pink...

(You'll have to keep on testing the cabbage-water indicator in after a day or two to see if the indicator quality persists or degrades.
6 0
3 years ago
Read 2 more answers
Given the formula: what is a chemical name of this compound? propane propanal propanol propanone
katrin [286]
1) Chemical formula for propane is CH₃-CH₂-CH₃. 
Propane is a three carbon alkane (acyclic saturated <span>hydrocarbon).
</span>2) Chemical formula for propanal is CH₃-CH₂-CH=O.
Propanal <span> is a </span>saturated<span> three carbon </span>aldehyde (have<span> a </span>carbonyl<span> center).
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1-propanol <span> is a </span><span>primary alcohol.
4) </span>Chemical formula for propanone is (CH₃)₂-C=O.
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7 0
3 years ago
The process in which an organic acid and an alcohol react to form an ester and water is known as esterification. Ethyl butanoate
egoroff_w [7]

Answer:

697 g

Explanation:

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C₂H₅OH + C₃H₇COOH → C₃H₇COOC₂H₅ + H₂O

The molar ratio of C₂H₅OH to C₃H₇COOC₂H₅ is 1:1. The moles of C₃H₇COOC₂H₅ produced from 6.00 moles of C₂H₅OH are:

6.00 mol C₂H₅OH × (1 mol C₃H₇COOC₂H₅/1 mol C₂H₅OH) = 6.00 mol C₃H₇COOC₂H₅

The molar mass of C₃H₇COOC₂H₅ is 116.16 g/mol. The mass corresponding to 6.00 mol is:

6.00 mol × (116.16 g/mol) = 697 g

7 0
3 years ago
At what temperature (in C) will a sample of gas occupy 91.3 L if it occupies 45.0 L at 70.0°C? Assume constant pressure.)
sdas [7]

Solution is here,

for initial case,

temperature(T1)=70°C=70+ 273=343K

vloume( V1) =45 L

for final case,

temperature( T2)=?

volume(V2)= 91.3 L

at constant pressure,

V1/V2 = T1/T2

or, 45/91.3 = 343/ T2

or, T2= (343×91.3)/45

or, T2=695.9 K = (695.9-273)°C=422.9°C

5 0
3 years ago
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