Question

In the following reaction, how many grams of ammonia (NH3) will react with 27.8 grams of nitric oxide (NO)? 4NH3 + 6NO → 5N2 + 6H2O The molar mass of ammonia is 17.0337 grams and that of nitric oxide is 30.01 grams.
a- 23.7 grams

b- 10.5 grams

c- 73.5 grams

d- 32.7 grams

Answer 1

The anwser is b10.5g

Answer 2

4NH₃ + 6NO → 5N₂ + 6H₂O

mol of NO  =  $\frac{mass of NO}{Molar Mass of NO}$
 
                  =  $\frac{27.8 g}{30.01 g / mol}$
                   
                  =  0.93 mol

Based on the balance equation mole ratio of NH₃  :  NO  is   4 : 6
                                                                                            =  2 : 3

If mol  of NO  =  0.93 mol

then mol of NH₃ = $\frac{0.93 mol * 2}{3}$
                           
                          =  0.62 mol

Mass of ammonia =  mol  ×  molar mass
          
                             =  0.62 mol   ×  17.03 g/mol
 
                             =  10.54 g

Therefore B is the best answer