If 15 grams of Carbon dioxide is produced in a chemical reaction, how many grams of Carbon must be consumed in the reaction if w
1 answer:
Answer:
Quantity of Carbon is 4.09 gm
Explanation:
Equation of carbon reacting with oxygen to give carbon dioxide is given by
C + ⇒ C
One mole of carbon reacts with one mole of Oxygen in this reaction to give One mole of Carbon dioxide.
So, 12 gm of carbon reacts with 32 gm of Oxygen in this reaction to give 44 gm of carbon dioxide.
15 gm of C was formed in this reaction
Oxygen used in this reaction = ×32 = 10.91 gm ,
Thus Oxygen is in sufficient quantity in the reaction.
Now,
Carbon that must be used = ×12 = 4.09 gm.
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The % yield of Ca(OH)₂ : 62.98%
<h3>Further eplanation </h3>Percent yield is the compare of the amount of product obtained from a reaction with the amount you calculated
General formula:
Percent yield = (Actual yield / theoretical yield )x 100%
An actual yield is the amount of product actually produced by the reaction. A theoretical yield is the amount of product that you calculate from the reaction equation according to the product and reactant coefficients
Reaction
CaO + H₂O ⇒ Ca(OH)₂
mass CaO= 4.2 g
mol CaO(MW=56,0774 g/mol) :
mol Ca(OH)₂ based on mol CaO
mol ratio CaO : Ca(OH)₂,= 1 : 1, so mol Ca(OH)₂ = 0.075
mass Ca(OH)₂(MW=74,093 g/mol) ⇒ theoretical
% yield :
Answer: The percent yield of the reaction is 77.0 %
Explanation:
According to stoichiometry:
2 moles of produces = 2 moles of
2.18 moles of is produced by=
of
Mass of =
percent yield =