Answer:
Quantity of Carbon is 4.09 gm
Explanation:
Equation of carbon reacting with oxygen to give carbon dioxide is given by
C + ⇒ C
One mole of carbon reacts with one mole of Oxygen in this reaction to give One mole of Carbon dioxide.
So, 12 gm of carbon reacts with 32 gm of Oxygen in this reaction to give 44 gm of carbon dioxide.
15 gm of C was formed in this reaction
Oxygen used in this reaction = ×32 = 10.91 gm ,
Thus Oxygen is in sufficient quantity in the reaction.
Now,
Carbon that must be used = ×12 = 4.09 gm.
Answer:
The ratio of the mass ratio of S to O; in SO, to the mass ratio of S to O; in SO₂, is 2:1
Explanation:
According to the consideration, let us first find the ratio of S and O in both the compounds
For SO:
Let us express it as
For SO₂,
Due to two oxygen atoms in the molecule, the mass of oxygen will be taken two times
Let us express it as
Now, for the ratio of both the above-calculated ratios,
The required ratio is 2:1
Answer:
a) Representation - (in attachment)
b) Tetrahedral geometry and
c) hybrid orbitals invovle sigma bonding.
orbitals are formed by the overlapping of d-orbitals of sulfur with p-orbitals of oxygen.
Explanation:
a)
Representation in attachment.
The overall charge in the both structures are -2. The structure (b) is favored by the resonance structures since the formal charge with in the species are remained.
Therefore, structure (b) is the better representation of sulfate ion.
b)
In sulfate ion, sulfur atom is attached with four different oxygen atoms. According to the VSEPR theory , the sufate ion has tetrahedral geometry.
There is four sigma bonds and zero lone pairs present on the central metal atom.
Hence, the hybridization of the sulfur atom is
c)
The s and p orbitals of sulfur invovles hybridization and form sigma bonds.The orbitals of sulfur involves bonding.
Therefore, bonds are formed by the overlapping of d-orbitals of sulfur with p-orbitals of oxygen.
Explanation:
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Answer: 0.011 moles.
Explanation:-
To calculate the moles, we use the equation:
Given :
Mass of copper = 0.71 g
Molar mass of copper = 63.5 g/mol
Putting i the values, we get:
Thus the number of moles of copper in 0.71 g of copper is 0.011 moles.