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iris [78.8K]
3 years ago
15

If 15 grams of Carbon dioxide is produced in a chemical reaction, how many grams of Carbon must be consumed in the reaction if w

e know there were 11 grams of Oxygen on the reactants side of the equation?
Chemistry
1 answer:
guajiro [1.7K]3 years ago
5 0

Answer:

Quantity of Carbon is 4.09 gm

Explanation:

Equation of carbon reacting with oxygen to give carbon dioxide is given by

C + O_{2} ⇒ CO_{2}

One mole of carbon reacts with one mole of Oxygen in this reaction to give One mole of Carbon dioxide.

So, 12 gm of carbon reacts with 32 gm of Oxygen in this reaction to give 44 gm of carbon dioxide.

15 gm of CO_{2} was formed in this reaction

Oxygen used in this reaction = \frac{15}{44}×32 = 10.91 gm ,

Thus Oxygen is in sufficient quantity in the reaction.

Now,

Carbon that must be used = \frac{15}{44}×12  = 4.09 gm.

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Imagine two solutions with the same concentration and the same boiling point, but one has benzene as the solvent and the other h
Degger [83]

Answer:

Molality of both benzene and carbon tetrachloride is 1.32 m .

boiling point is 83.4396 °C

Explanation:

When a non-volaile solute is added to a solvent, its boiling point increases. The relationship increase in temperature and molality of the solute is given as follows:

ΔT = m × Kb

Boiling point of pure benzene is 80.1 °C.

Molal elevation boiling constant of benzene (k_b) is 2.53 °C/m

Increase in boiling point of benzene = m × 2.53

Therefore, Boiling point of benzene solution = 80.1 + 2.53m

Boiling point of pure carbon tetrachloride is 76.8 °C

Molal elevation boiling constant of carbon tetrachloride (k_b) is 5.03 °C/m

Increase in boiling point of benzene = m × 5.03

Therefore, Boiling point of carbon tetrachloride solution = 76.8 + 5.03m

It is given that boiling point of both the solutions are same therefore,

76.8 + 5.03m = 80.1 + 2.53m

5.03m - 2.53m = 80.1 - 76.8

2.5m = 3.3

m = 1.32  

Molality of both benzene and carbon tetrachloride is 1.32 m

Boiling point of the solutions = 80.1 + 2.53 × 1.32

                                            = 83.4396 °C

6 0
3 years ago
Our skies are blue because of what kind of light? (for my science class pls help- :<)
iren2701 [21]

Answer:

"Gases and particles in Earth's atmosphere scatter sunlight in all directions. Blue light is scattered more than other colors because it travels as shorter, smaller waves. This is why we see a blue sky most of the time."

4 0
3 years ago
Read 2 more answers
Cinnamon owes its flavor and odor to cinnamaldehyde (C9H8O). Determine the boiling point elevation of a solution of 92.7 mg of c
Flauer [41]

Answer:

The boiling point elevation is 3.53 °C

Explanation:

∆Tb = Kb × m

∆Tb is the boiling point elevation of the solution

Kb is the molal boiling point elevation constant of CCl4 = 5.03 °C/m

m is the molality of the solution is given by moles of solute (C9H8O) divided by mass of solvent (CCl4) in kilogram

Moles of solute = mass/MW =

mass = 92.7 mg = 92.7/1000 = 0.0927 g

MW = 132 g/mol

Moles of solute = 0.0927/132 = 7.02×10^-4 mol

Mass of solvent = 1 g = 1/1000 = 0.001 kg

m = 7.02×10^-4 mol ÷ 0.001 kg = 0.702 mol/kg

∆Tb = 5.03 × 0.702 = 3.53 °C (to 2 decimal places)

6 0
3 years ago
Whats does x stand for?
Furkat [3]

x is the chemical symbol of the element and it must correspond to the atomic number

4 0
2 years ago
If 38.5 grams of potassium react with excess oxygen gas, how many grams of potassium oxide can be produced? 4K + O2 yields 2K2O
Lera25 [3.4K]

Answer:

46.40 g.

Explanation:

  • It is a stichiometric problem.
  • The balanced equation of the reaction: 4K + O₂ → 2K₂O.
  • It is clear that 4.0 moles of K reacts with 1.0 mole of oxygen produces 2.0 moles of K₂O.
  • We should convert the mass of K (38.5 g) into moles using the relation:

<em>n = mass / molar mass,</em>

n = (38.5 g) / (39.098 g/mol) = 0.985 mole.

<em>Using cross multiplication:</em>

4.0 moles of K produces → 2.0 moles of K₂O, from the stichiometry.

0.985 mole of K produces → ??? moles of K₂O.

∴ The number of moles of K₂O produced = (0.985 mole) (2.0 mole) / (4.0 mole) = 0.4925 mole ≅ 0.5 mole.

  • Now, we can get the mass of K₂O:

∴ mass = n x molar mass = (0.5 mole) (94.2 g/mol) = 46.40 g.

6 0
3 years ago
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