Answer:
all elements have a different atomic number
Explanation:
Atomic number of element does not affect their reactions with others
Answer: 131 g of bromine is required.
Explanation:
The balanced equation will be :
To calculate the moles, we use the equation:
moles of 
According to stoichiometry :
2 moles of require = 3 moles of 
Thus 0.544 moles of require=
of
Mass of 
Thus 131 g of bromine is required.
A)2nd period - Li, Be, B,C,N,O,F,Ne
b)Metalls of the 2nd period are Li,Be
Answer:
pH = 1.5
Explanation:
The pH is always equal to -log[H+].
Simply plug it into this formula to find the pH. In order to find the concentration from the pH, you can do:
= [H+]
Answer:We are already given with the mass of the Xe and it is 5.08 g. We can calculate for the mass of the fluorine in the compound by subtracting the mass of xenon from the mass of the compound.
mass of Xenon (Xe) = 5.08 g
mass of Fluorine (F) = 9.49 g - 5.08 g = 4.41 g
Determine the number of moles of each of the element in the compound.
moles of Xenon (Xe) = (5.08 g)(1 mol Xe / 131.29 g of Xe) = 0.0387 mols of Xe
moles of Fluorine (F) = (4.41 g)(1 mol F/ 19 g of F) = 0.232 mols of F
The empirical formula is therefore,
Xe(0.0387)F(0.232)
Dividing the numerical coefficient by the lesser number.
XeF₆
Explanation:
