Answer:
x⁷+7x⁶+21x⁵+35x⁴+35x³+21x²+7x+1
Step-by-step explanation:
(x + 1)⁷: Pascal's Triangle for (a+b)⁷
a₇+7a⁶b+21a⁵b²+35a⁴b³+... + 7a¹b⁶ + b⁷
x⁷+7x⁶+21x⁵+35x⁴+35x³+21x²+7x+1
7, 13, 19 and 25 have a common difference: 6.
6 added to 7 gives us 13; 6 added to 13 gives us 19, and so on.
Explicit formula: a(n) = 7 + 6(n-1), where 7 is the first term and n is the counter (1, 2, 3, ...).
The first term is 7 (given). This corresponds to n=1.
The second term is a(2) = 7 + 6(2-1), or 7 + 6, or 13. This corresponds to n = 2.
and so on.
This is an optimization calculus problem where you would need to know a little bit more about the box, atleast i would think. You would just need to use the volume equation of a sphere as the restrictive equation in the optimization problem. Perhaps there is a way to solve with the given information, but i do not know how to.
9514 1404 393
Answer:
2) x = 7
3) x = 5
Step-by-step explanation:
When a transversal crosses parallel lines, all of the acute angles are congruent, and all of the obtuse angles are congruent. When it crosses at right angle, all of the angles are right angles.
2) All of the angles are right angles.
11x +13 = 90
11x = 77 . . . . . . subtract 13
x = 7 . . . . . . . divide by 11
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3) The two marked angles are acute.
16x = 80 . . . . the acute angles are congruent
x = 5 . . . . . . divide by 16
The answer is 16. because the 4 lines up with the 16
