Answer:
4893.7 J
Explanation:
TH = 100°C = 373 K
Tc = 0°C = 273 K
Heat rejected is used to melt ice
So, Qc = mass of ice x latent heat of fusion
Qc = 0.04 x 334 x 1000 = 13360 J
So,
QH = 18253.7 J
Work = QH- Qc = 18253.7 - 13360
W = 4893.7 J
Answer:
Increasing the launch height increases the downward distance, giving the horizontal component of the velocity greater time to act upon the projectile and hence increasing the range.
Explanation:
Answer:
1) Time period
2) amplitude
3) Hertz or hz
4) Noise
5) frequency
6) infrasonic and ultrasonic
7) solid liquid and gas
8) A man
9) energy
10)1 vibration per minute
Answer:
a) If the mass get double then the potential of the spring gets four times.
b) P'=3.848 J
Explanation:
Given that
P= 0.962 J
m = 3.5 kg
m'= 7 kg
Lets take extension in the spring is x when the mass 3.5 kg is attached to the spring.
m g = K x
K=Spring constant
We know that potential energy given as
If the mass get double then the potential of the spring gets four times.
P'= 4 P
When mass ,m' = 7 kg
Then potential will be
-----1
-------2
From equation 1 and 2
P'= 4 x 0.962 J
P'=3.848 J
Answer:
<h3>25.152m</h3>
Explanation:
Compete question;
A roller coaster has a loop in which the centripetal acceleration equals 9.8m/s² . If the tangential speed of the roller coaster cars is 15.7 m/s, find its radius.
centripetal acceleration a = v²/r
v is the tangential speed
r is the radius
Given
v = 15.7m/s
a = 9.8m/s²
9.8 = 15.7²/r
9.8r = 15.7²
r = 15.7²/9.8
r = 246.49/9.8
r = 25.152m
Hence the radius of the coaster is 25.152m