Answer:
Depends on what pole it is.
Explanation:
If the poles of the cars and magnets are the same they will repel, if different, attracts.
Answer:
F = ⅔ F₀
Explanation:
For this exercise we use Coulomb's law
F = k q₁q₂ / r²
let's use the subscript "o" for the initial conditions
F₀ = k q² / r²
now the charge changes q₁ = q₂ = 2q and the new distance is r = 3 r
we substitute
F = k 4q² / 9 r²
F = k q² r² 4/9
F = ⅔ F₀
Answer: D.) electromagnetic induction
Explanation: Electroctromagnetic induction may be explained as a process whereby electric current is induced or produced by difference in potential resulting from the movement of conductor across a magnetic field.
In simple terms, an electromotive force is induced when a magnet is moved through a conducting loop.
The electromotive force produced by moving a magnet through a conducting loop can be represented by the relation:
E = - N (dΦ / dt)
Where E = electromotive force in voltage
N = number of loop in conductor
dΦ = change in magnetic Flux
dt = change in time
Answer:
Los objetos A y C tienen cargas del mismo signo (opcion a)
Explanation:
Hay dos tipos de cargas
: cargas positivas y cargas negativas.
La Ley de Coulomb dice que la fuerza electrostática entre dos cargas puntuales es proporcional al producto de las cargas e inversamente proporcional al cuadrado de la distancia que las separa, y tiene la dirección de la línea que las une y se cumple que:
- La fuerza ejercida sobre una carga apunta hacia la otra cuando las dos tienen distinto signo (fuerza atractiva).
- El sentido de la fuerza se dirige hacia el lado opuesto de la carga cuando ambas tienen el mismo signo (fuerza repulsiva).
Es decir que las cargas de igual signo se repelen, mientras que las de diferente signo se atraen.
Entonces, si se juntan los objetos A y B y se repelen significa que la carga es del mismo signo.
Cuando se acercan los objetos B y C, se repelen. Entonces significa que posee carga de igual signo.
Por lo que podes concluir que <u><em>los objetos A y C tienen cargas del mismo signo (opcion a)</em></u>
Answer:
2.64 x 10⁻⁶T
Explanation:
The magnitude of the magnetic field produced by a long straight wire carrying current is given by Biot-Savart law as follows: "The magnetic field strength is directly proportional to the current on the wire and inversely proportional to the distance from the wire". This can be written mathematically as;
B = (μ₀ I) / (2π r) ----------------(i)
B is magnetic field
I is current through the wire
r is the distance from the wire
μ₀ is the magnetic constant = 4π x 10⁻⁷Hm⁻¹
From the question;
I = 0.7A
r = 0.053m
Substitute these values into equation (i) as follows;
B = (4π x 10⁻⁷ x 0.7) / (2π x 0.053)
B = 2.64 x 10⁻⁶T
Therefore the approximate magnitude of the magnetic field at that location is 2.64 x 10⁻⁶T
