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KATRIN_1 [288]
2 years ago
15

9) For a horizontally launched projectile, decreasing the height of the

Physics
1 answer:
Volgvan2 years ago
4 0

Answer:

Increasing the launch height increases the downward distance, giving the horizontal component of the velocity greater time to act upon the projectile and hence increasing the range.

Explanation:

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what gravitational force does the moon produce on the earth is their centers are 3.88x10(8)m apart and the moon has a mass of 7.
yawa3891 [41]

Isaac Newton compared the acceleration of the moon to the acceleration of objects on earth. Believing that gravitational forces were responsible for each, Newton was able to draw an important conclusion about the dependence of gravity upon distance. This comparison led him to conclude that the force of gravitational attraction between the Earth and other objects is inversely proportional to the distance separating the earth's center from the object's center. But distance is not the only variable affecting the magnitude of a gravitational force. Consider Newton's famous equation

Read more on Brainly.com - brainly.com/question/12278932#readmore

4 0
3 years ago
Which value would complete the last cell?
GREYUIT [131]

Answer:

4.0

Explanation:

The following data were obtained from the question:

Force (F) = 20 N

Mass (m) = 5 kg

Acceleration (a) =.?

Force is simply defined as the product of mass and acceleration. Mathematically, it is expressed as

Force (F) = mass (m) x acceleration (a)

F = ma

With the above formula, we can obtain th acceleration of the body as follow:

Force (F) = 20 N

Mass (m) = 5 kg

Acceleration (a) =.?

F = ma

20 = 5 x a

Divide both side by 5

a = 20/5

a = 4 m/s²

Therefore, the value that will complete the last cell in the question above is 4.

5 0
4 years ago
An object is moving east with a constant speed of 30 m/s for 5 seconds. What is the object’s acceleration?
Shtirlitz [24]

Answer:

6 m/s²

Explanation:

From the question given above, the following data were obtained:

Velocity (v) = 30 m/s

Time (t) = 5 s

Acceleration (a) =..?

Acceleration is defined mathematically as:

Acceleration (a) = Velocity (v) /time (t)

a = v /t

With the above formula, we can obtain the acceleration of the object as follow:

Velocity (v) = 30 m/s

Time (t) = 5 s

Acceleration (a) =..?

a= v/t

a= 30/5

a = 6 m/s²

Therefore, the acceleration of the object is 6 m/s² due East.

7 0
4 years ago
Problem 5 You are playing a game where you drop a coin into a water tank and try to land it on a target. You often find this gam
Dvinal [7]

Answer:

Option D: 1.5in in front of the target

Explanation:

The object distance is y= 6in.

Because the surface is flat, the radius of curvature is infinity .

The incident index is n_i=\frac{4}{3} and the transmitted index is n_t= 1.

The single interface equation is \frac{n_i}{y}+\frac{n_t}{y^i}=\frac{n_t-n_i}{r}

Substituting the quantities given in the problem,

\frac{\frac{4}{3}}{6in}+\frac{1}{y^i}= 0

The image distance is then y^i=-\frac{18}{4}in =-4.5in

Therefore, the coin falls 1.5in in front of the target

6 0
3 years ago
While sitting in a moving bus you throw an apple up into the air. The apple will land back into your hand.
Neko [114]
False because you have moved after you through the apple in the air
6 0
3 years ago
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