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VashaNatasha [74]
3 years ago
7

Oof please help last question (maybe)-

Mathematics
2 answers:
Orlov [11]3 years ago
8 0
5 1/2 is the answer

Have a nice day! :)
Phoenix [80]3 years ago
7 0

Answer:

it should be 5 and a half I am like 98.9 percent sure

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44. Express each of these system specifications using predicates, quantifiers, and logical connectives. a) Every user has access
DENIUS [597]

Answer:

a. ∀x (User(x) → (∃y (Mailbox(y) ∧ Access(x, y))))

b. FileSystemLocked → ∀x Access(x, SystemMailbox)

c. ∀x ∀y ((Firewall(x) ∧ Diagnostic(x)) → (ProxyServer(y) → Diagnostic(y))

d. ∀x (ThroughputNormal ∧(ProxyServer(x)∧ ¬Diagnostic(x))) → (∃y Router(y)∧Functioning(y))

Step-by-step explanation:

a)  

Let the domain be users and mailboxes. Let User(x) be “x is a user”, let Mailbox(y) be “y is a mailbox”, and let Access(x, y) be “x has access to y”.  

∀x (User(x) → (∃y (Mailbox(y) ∧ Access(x, y))))  

(b)

Let the domain be people in the group. Let Access(x, y) be “x has access to y”. Let FileSystemLocked be the proposition “the file system is locked.” Let System Mailbox be the constant that is the system mailbox.  

FileSystemLocked → ∀x Access(x, SystemMailbox)  

(c)  

Let the domain be all applications. Let Firewall(x) be “x is the firewall”, and let ProxyServer(x) be “x is the proxy server.” Let Diagnostic(x) be “x is in a diagnostic state”.  

∀x ∀y ((Firewall(x) ∧ Diagnostic(x)) → (ProxyServer(y) → Diagnostic(y))  

(d)

Let the domain be all applications and routers. Let Router(x) be “x is a router”, and let ProxyServer(x) be “x is the proxy server.” Let Diagnostic(x) be “x is in a diagnostic state”. Let ThroughputNormal be “the throughput is between 100kbps and 500 kbps”. Let Functioning(y) be “y is functioning normally”.  

∀x (ThroughputNormal ∧(ProxyServer(x)∧ ¬Diagnostic(x))) → (∃y Router(y)∧Functioning(y))

4 0
3 years ago
Plz help me with this. Thank you!
Tresset [83]

Answer:

58 units

Step-by-step explanation:

7 \times 10 = 70

6 \times 2 = 12

70 - 12 = 58

4 0
3 years ago
Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth. x2 + 3 = 9x a 0.35, -8.65 b -0.35
Tema [17]
1. You have the following quadratic equation and to solve it, you must follow the steps below:
<span> 
 x</span>²<span>+3=9x
 
 2. The form of the equation that you need to apply the quadratic formula, is:
 
 ax</span>²+bx+c=0
<span> 
 3. Then:
</span> 
 x²<span>+3=9x
</span> x²-9x<span>+3=0
</span><span> 
 4. The quadratic formula is shown below:
 
 x=(-b±√(b^2-4ac))/2a
 
 5. Then, you have:
 
 a=1
 b=-9
 c=3
 
 6. When you substitute the values into the quadratic formula, you obtain:
 
 x1=0.34
 x2=8.65</span>
6 0
3 years ago
F(5)=3|x+11|-4, find f(5)
deff fn [24]

Answer:

f(5) = 44

Step-by-step explanation:

f(x) = 3|x+11| -4

let x =5

f(5) = 3|5+11| -4

     = 3|16| -4

      = 3*16 -4

    = 48 -4

   = 44

5 0
3 years ago
Read 2 more answers
$18 less than the original price is $48.<br><br> HELP!!
mihalych1998 [28]

Answer:

i believe itd be 66 dollars :D

hope this helps !!

Step-by-step explanation:

x - 18 = 48

add 48 and 18 and get the answer = $66

4 0
3 years ago
Read 2 more answers
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