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kap26 [50]
3 years ago
7

How fast a reactant is used up to how fast a product is formed is _____.

Chemistry
1 answer:
STatiana [176]3 years ago
5 0

Answer:   B) The rate of reaction

Explanation:  Rate of reaction describes the speed at which the reactants of the reaction are getting converted into the products with respect to time.

The equilibrium explains that how much concentration of reactant is in equilibrium with the product.

Solution concentration is the number of moles of solution divided by volume.

The catalyst is the substance which increases the rate of the reaction which bringing any change in other things.

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Answer:

-low specific heat

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A precipitate is a solid that sometimes forms when two liquids combine.<br> A true <br> B False
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<h2>Question:</h2>

A precipitate is a solid that sometimes forms when two liquids combine.

<h2>Answer:</h2>

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2 years ago
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The formation of ammonia is represented by the equation N2(g) + 3H2(g) ⇌ 2NH3(g). Determine the enthalpy of formation of ammonia
Savatey [412]

Answer:

\Delta _fH_{NH_3}=-66\frac{kJ}{mol}

Explanation:

Hello!

In this case, since the study of the bond energy allows us to compute the enthalpies of some reactions, for this combination reaction by which ammonia is yielded, we understand the enthalpy of reaction equals the enthalpy of formation of ammonia, and, in terms of the bonds energy we can write:

\Delta _fH_{NH_3}=Delta _rH=\Sigma \Delta H(bonds \ broken)-\Sigma \Delta H(bonds \ formed)

Whereas the bonds enthalpy of those bonds that get broken cover the N≡N and the three H-H bonds at the reactants side and the enthalpy of those bonds that are formed cover the six N-H bonds at the products; which means we obtain:

\Delta _fH_{NH_3}=942\frac{kJ}{mol} +3*436\frac{kJ}{mol}-6*386\frac{kJ}{mol}\\\\\Delta _fH_{NH_3}=-66\frac{kJ}{mol}

Which differs from the theoretical value that is -46 kJ/mol.

Best regards!

7 0
3 years ago
How is the atomic mass of an element calculated?
zloy xaker [14]

Answer:

Mass number (A) is the number of nucleons (proton and neutron) present in a atom.

Explanation:

electrons don't cout since they are thousandth's of the mass of protons or neutrons

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