Answer:
The mass number of the stable daughter product is 208
Explanation:
First thing's first, we have to write out the equation of the reaction. This is given as;
²³²₉₀Th → 6 ⁴₂α + 4 ⁰₋₁ β + X
In order to obtain the identity of X, we have to obtain it's mass numbers and atomic number.
There is conservation of matter so we expect the mass number to remain the same in both the reactant and products.
Mass Number
Reactant = 232
Product = (6* 4 = 24) + (4 * 0 = 0) + x = 24 + x
since reactant = product
232 = 24 + x
x = 232 - 24 = 208
Atomic Number
Reactant = 90
Product = (6* 2 = 12) + (4 * -1 = -4) + x = 8 + x
since reactant = product
90 = 8 + x
x = 90 - 8 = 82
Answer:
3.94 × 10³ g
Explanation:
Step 1: Write the neutralization reaction
HClO₃ + NaOH = NaClO₃ + H₂O
Step 2: Calculate the moles of chloric acid that react
25.5 L of 3.86 M chloric acid is to be neutralized. The reacting moles are:
Step 3: Calculate the required moles of sodium hydroxide
The molar ratio of HClO₃ to NaOH is 1:1. Then, the reacting moles of NaOH are 98.4 moles.
Step 4: Calculate the mass of sodium hydroxide corresponding to 98.4 moles
The molar mass of NaOH is 40.00 g/mol.
Answer:
D. 9.
Step-by-step explanation:
One formula unit of NaOH contains <em>three atoms</em>: 1 Na, 1 O, and 1 H.
3 formula units × (3 atoms/1 formula unit) = 9 atoms
