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tankabanditka [31]

3 years ago

10

A personality test may be given to assess what?

1 answer:

Strike441 [17]3 years ago

6 0

To assess yourself.... To know yourself more..

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Suppose that an individual has a body fat percentage of 18.8% and weighs 131 pounds. how many pounds of her weight is made up of

balu736 [363]

X weight 131
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18.8% 100%

Cross multiply and get 24.6 pounds

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To function properly, a rainwater outflow pipe must drop 1 inch every 25 inches of horizontal distance. A 40 feet long rainwater

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it must drop 1.6 inches on each end i believe.

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(30 POINTS) see image and evaluate

adelina 88 [10]

Answer:

1/400

Step-by-step explanation:

i put it in the calculator and got 1/400

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Porphyrin is a pigment in blood protoplasm and other body fluids that is significant in body energy and storage.

ra1l [238]

Answer:

a) 0.923

b) 0.957

c) 0.88

d) 0.077

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 40

Standard Deviation, σ = 14

We are given that the distribution of number of milligrams of porphyritic per deciliter of blood is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P(xis less than 60)

P(x < 60)

$P( x < 60) = P( z < \displaystyle\frac{60 - 40}{14}) = P(z < 1.4285)$

Calculation the value from standard normal z table, we have,

$P(x < 60 ) =0.923 = 92.3\%$

b) P(x is greater than 16)

$P(x > 16) = P(z > \displaystyle\frac{16-40}{14}) = P(z > -1.7142)\\\\P( z > -1.7142) = 1 - P(z \leq -1.7142)$

Calculating the value from the standard normal table we have,

$1 - 0.043 = 0.957 = 95.7\%\\P( x > 16) = 95.7\%$

c)P(x is between 16 and 60)

$P(16 \leq x \leq 60) = P(\displaystyle\frac{16 - 40}{14} \leq z \leq \displaystyle\frac{60-40}{14}) = P(-1.7142 \leq z \leq 1.4285)\\\\= P(z \leq 1.4285) - P(z < -1.7142)\\= 0.923 - 0.043= 0.88 = 88%$

$P(16 \leq x \leq 60) = 88\%$

d) P(x is more than 60)

P(x > 60) = 1 - P(x < 60) = 1 - 0.923 = 0.077

6 0

3 years ago