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Colt1911 [192]
3 years ago
12

What did Robert Millikan's oil drop experiment prove?

Chemistry
2 answers:
joja [24]3 years ago
7 0

Answer:

Robert Millikan was a well known experimental physicist. Robert Millikan's oil drop experiment proved that it determined the actual mass of the electron.

creativ13 [48]3 years ago
6 0
Robert Millikan's oil drop experiment proved that it determined the actual mass of the electron. Robert Millikan was a well known experimental physicist. 
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some components of ink are minimally attracted to the stationary phase and very soluble in the solvent. where are these componen
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They’ll have moved the farthest, since the solvent is best at carrying those kinds of materials.
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Kory goes outside to grill some hamburgers. He tells Ethan that when you cook meat, a chemical reation is taking place. Ethan sa
Ray Of Light [21]

Answer:

Explanation:

Kory goes outside to grill some hamburgers. He tells Ethan that when you cook meat, a chemical reation is taking place. Ethan says "That's perpostrous!" Is Kory Correct??

absolutely Kory is correct

evidence of a chemical reaction are

new odor and or taste

change in color

signs of bubbling

direct effect of temperature on rate of change

evidence of a new substance being formed

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7 0
3 years ago
The mass of an atom may be found by adding the
Darina [25.2K]

Answer:

protons and neutrons

Explanation:

5 0
3 years ago
4.85 x 10^-4 tons to cups
fiasKO [112]

Answer:

2.08753919851 cups

0.464942810185139 cups

2.08753919851 cups

Explanation:

i looked it up

7 0
3 years ago
A weather balloon is filled with helium that occupies a volume of 5.37 104 L at 0.995 atm and 32.0°C. After it is released, it r
svp [43]

Answer:

The new volume is 63583 L

Explanation:

Step 1: Data given

The initial volume of the balloon = 5.37 * 10^4 L

The initial pressure = 0.995 atm

The initial temperature = 32.0 °C = 305.15 K

The pressure decreased to 0.720 atm

The temperature decreased to -11.7 °C = 261.45 K

Step 2: Calculate the new volume

P1*V1 / T1 = P2*V2/T2

⇒with P1 = the initial pressure = 0.995 atm

⇒with V1 = the initial volume = 5.37 *10^4 L

⇒with T1 = the initial temperature = 305.15 K

⇒with P2 = the decreased pressure = 0.720 atm

⇒with V2 = the new volume = TO BE DETERMINED

⇒with T2 = the decreased temperature : 261.45 K

(0.995 * 5.37*10^4)/305.15 = (0.720 * V2) / 261.45

V2 = 63583 L

The new volume is 63583 L

8 0
3 years ago
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