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julsineya [31]
4 years ago
13

The water bottle contains 575 grams of water at 80°C. The water eventually cools to

Chemistry
1 answer:
Jet001 [13]4 years ago
8 0

Answer:

–23000 Calories.

NOTE : The negative sign indicates that heat has been loss to the student back.

Explanation:

The following data were obtained from the question:

Mass (M) of water = 575 g

Initial temperature (T1) = 80 °C

Final temperature (T2) = 40 °C

Heat (Q) transferred =.?

Next, we shall determine the change in temperature (ΔT).

This is illustrated below:

Initial temperature (T1) = 80 °C

Final temperature (T2) = 40 °C

Change in temperature (ΔT) =?

Change in temperature (ΔT) = T2 – T1

Change in temperature (ΔT) = 40 – 80

Change in temperature (ΔT) = –40°C

Finally, we shall determine the heat transferred. This can be obtained as follow:

Mass (M) of water = 575 g

Change in temperature (ΔT) = –40°C

Specific heat capacity (C) of water = 1 Cal/g°C

Heat (Q) transferred =.?

Q = MCΔT

Q = 575 × 1 × –40

Q = –23000 Calories

NOTE : The negative sign indicates that heat has been loss to the student back.

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Answer:

Conclusion

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I believe you were asking for the term that best matches with the description given. Typically the conclusion summarizes your experiment in a 1 to 2 paragraph format.

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A 4.0 L container stores 4.0 grams of an unknown gas at 2.3 atm of pressure and 30.0 degrees Celsius. What is the molar mass of
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Which interaction produces dispersive forces by creating temporary dipoles that induce dipoles in other molecules?
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This interaction must be one of the intermolecular forces, particularly, Van der Waals forces. From the description given, this force is called <em>induced dipole-induced dipole forces</em>. Dipole is defined as the separation of positive and negative charges. This type of intermolecular force is very weak compared to hydrogen bonding.
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3 years ago
Oxygen gas, generated by the reaction 2KClO3(s)-&gt;2KCl(s)+3O2(g) is collected over water at 27°C in a 1.55 L vessel at a total
KonstantinChe [14]

Answer:

Explanation:

Use Dalton's law and the vapor pressure of water at 23.0 o C to correct the pressure to units of atmoshperes.

PT = Poxygen +Pwater

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762 mmHg = Poxygen + 21.1 mmHg

Poxygen = 762 mmHg - 21.1 mmHg

Poxygen =741 mmHg

Convert the corrected pressure to atmospheres.

(741 mmHg) (1 atm / 760 mmHg) = 0.975 atm

Use the ideal gas law to find out how many moles of gas were produced:

PV = nRT (remember to put volume in liters and temperature in Kelvin)

(0.975 atm) (.193 L) = n (.0821 L atm / mol K) (298 K)

n = (0.975 atm) (.193 L) / (.0821 L atm / mol K) (298 K)

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4 0
3 years ago
Complete the table below by filling in the principal quantum number n and angular momentum quantum number l for each electron su
Alja [10]

Answer:

For 4f  the principal quantum number, n is 4 and the angular momentum quantum number l is 3

7s: n = 7 and l = 0

4p: n = 4 and l = 1

7p: n = 7 and l = 1

Explanation:

The principal quantum number gives the energy level of the electron in an atom. It shows the shells in which an electron is in an atom.

if n = 1, 2, 3, 4...; it corresponds to K, L, M, N... shells in an atom

The numerical coefficient of the subshell gives the pricipal quantum number.

for instance in 4f, the principal quantum number, n is 4  because 4 is the coefficient.

The angular momentum quantum number, l gives the energy sublevel or subshell.

Angular momentum quantum number has integral values, l = 0, 1, 2, 3... which correspond to  s, p, d, f,..  orbitals.

Thus for 4f  the principal quantum number, n is 4 and the angular momentum quantum number l is 3

similarly, for 7s: n = 7 and l = 0

4p: n = 4 and l = 1

7p: n = 7 and l = 0

using similar approach for others

3 0
3 years ago
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