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3 years ago

The water bottle contains 575 grams of water at 80°C. The water eventually cools to

Chemistry

1 answer:

Jet001 [13]3 years ago

8 0

Answer:

–23000 Calories.

NOTE : The negative sign indicates that heat has been loss to the student back.

Explanation:

The following data were obtained from the question:

Mass (M) of water = 575 g

Initial temperature (T1) = 80 °C

Final temperature (T2) = 40 °C

Heat (Q) transferred =.?

Next, we shall determine the change in temperature (ΔT).

This is illustrated below:

Initial temperature (T1) = 80 °C

Final temperature (T2) = 40 °C

Change in temperature (ΔT) =?

Change in temperature (ΔT) = T2 – T1

Change in temperature (ΔT) = 40 – 80

Change in temperature (ΔT) = –40°C

Finally, we shall determine the heat transferred. This can be obtained as follow:

Mass (M) of water = 575 g

Change in temperature (ΔT) = –40°C

Specific heat capacity (C) of water = 1 Cal/g°C

Heat (Q) transferred =.?

Q = MCΔT

Q = 575 × 1 × –40

Q = –23000 Calories

NOTE : The negative sign indicates that heat has been loss to the student back.

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How many grams of mercury would be contained in 15 compact fluorescent light bulbs?

zhenek [66]

Answer:

Grams of mercury= 0.06 g of Hg

Note: The question is incomplete. The complete question is as follows:

A compact fluorescent light bulb contains 4 mg of mercury. How many grams of mercury would be contained in 15 compact fluorescent light bulbs?

Explanation:

Since one fluorescent light bulb contains 4 mg of mercury,

15 such bulbs will contain 15 * 4 mg of mercury = 60 mg

1 mg = 0.001 g

Therefore, 60 mg = 0.001 g * 60 = 0.06 g of mercury.

Compact fluorescent lightbulbs (CFLs) are tubes containing mercury and noble gases. When electricity is passed through the bulb, electron-streams flow from a tungsten-coated coil. They collide with mercury atoms, exciting their electrons and creating flashes of ultraviolet light. A phosphor coating on the inside of the tube absorbs this UV light flashes and re-emits it as visible light. The amount of mercury in a fluorescent lamp varies from 3 to 46 mg, depending on lamp size and age.

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3 years ago

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BabaBlast [244]

Answer:

6. O₂ + Cu —> CuO

7. H₂ + Fe₂O₃ —> H₂O + Fe

8. O₂ + H₂ — > H₂O

9. H₂S + NaOH —> Na₂S + H₂O

10. Al + HCl —> H₂ + AlCl₃

Explanation:

6. Oxygen gas react with solid copper metal to form copper(II) oxide

Oxygen gas => O₂

Copper => Cu

copper(II) oxide => CuO

The equation is:

O₂ + Cu —> CuO

7. hydrogen gas and iron(III) oxide powder react to form liquid water and solid iron power

hydrogen gas => H₂

Iron(III) oxide => Fe₂O₃

Water => H₂O

Iron => Fe

The equation is:

H₂ + Fe₂O₃ —> H₂O + Fe

8. Oxygen gas react with hydrogen gas to form liquid water

Oxygen gas => O₂

hydrogen gas => H₂

Water => H₂O

The equation is:

O₂ + H₂ — > H₂O

9. Hydrogen sulphide gas is bubbled through a sodium hydroxide solution to produce sodium sulphide and liquid water

hydrogen sulphide => H₂S

sodium hydroxide => NaOH

Sodium sulphide => Na₂S

Water => H₂O

The equation is:

H₂S + NaOH —> Na₂S + H₂O

10. Hydrogen gas and aluminum chloride solutions are produced when solid aluminum react with hydrochloric acid

Aluminum => Al

Hydrochloric acid => HCl

hydrogen gas => H₂

Aluminum chloride => AlCl₃

The equation is:

Al + HCl —> H₂ + AlCl₃

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2 years ago

A piece of solid carbon dioxide with a mass of 5.50 grams is placed in a 10 Liter vessel that already contains 705 torr at 24 Ce

alex41 [277]

total pressure = ( 705 torr + 231.525torr) = 936.525torr

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3 years ago

Read 2 more answers

A typical coffee mug holds about 355,000 microliters of liquid. How many kiloliters of liquid does this mug hold expressed in st

skad [1K]

Answer:

$3.55\times 10^{-4}\ kL$

Explanation:

Given that,

A typical coffee mug holds about 355,000 microliters of liquid.

$1\ \mu L=10^{-6}\ L$

Also, 1 L = 0.001 kL

$10^{-6}\ L=0.001\times 10^{-6}\ kL\\\\=10^{-9}\ kL$

So, a typical coffee mug holds about $355000 \times 10^{-9}\ kL$ or $0.000355\ kL$ of liquid.

We need to convert it into Scientific notation.

We will shift 4 zeros to right. As a result,

$V=3.55\times 10^{-4}\ kL$

So, the mug will hold $3.55\times 10^{-4}\ kL$ of liquid.

3 0

3 years ago

Explain the two main physical/ chemical processes by which carbon dioxide molecules in the air move to the cells of phytoplankto

VARVARA [1.3K]

Answer:

The two physical/ chemical processes by which carbon dioxide molecules in the air move to the cells of phytoplankton in the ocean are the photosynthesis and the biological carbon pump.

Explanation:

The biological carbon pump is the action of organisms to move carbon during chemical and biological interactions from the surface into the deeper ocean and then to rocks.

The biological carbon pump its composed of three processes, which are the photosynthesis, the gravity and the food web interactions. They are all part of the carbon cycle.

During the photosynthesis, the phytoplankton take up carbon dioxide from the atmosphere that is dissolved in the surface water, and receives the energy from the sun to turn it into glucose and oxygen.

In the cells of the phytoplankton, glucose is transformed into other organic compounds. This material has organic carbon that can end in two ways: it is incorporated to marine organisms during the food web interactions or it can be remineralised forming calcium carbonate in the ocean surface.

The remineralization can be done by many organisms to build its shells or skeletons, or by chemical processes that happen in the ocean. This process allows more carbon dioxide to enter the water and to continue the cycle.

So when marine organisms die, all its organic components sink into the bottom of the ocean and carbon-rich sediments are form. And after millions of years, these sediments turn into rocks after going through chemical and physical phenomenon.

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3 years ago