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olga2289 [7]
2 years ago
13

Hcl and 1-isopropylcyclohexane formation

Chemistry
2 answers:
Vanyuwa [196]2 years ago
8 0

Answer:

Spahgetti

Explanation:

Grace [21]2 years ago
3 0
Yes I don’t know what this means
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A piston has an initial volume of 1.643 L at a pressure of 128 kPa. The temperature is maintained at 27 oC as the volume is decr
aivan3 [116]

Answer:

  • <u>355 kPa</u>

Explanation:

The ideal gases follow Boyle's law: at constant temperature pressure and volume are inversely related:

       PV=constant

       P_1V_1=P_2V_2

       P_2=\dfrac{P_1V_1}{V_2}

Subsituting and computing:

     P_2=\dfrac{1.643L\times 128kPa}{0.593L}\approx355kPa

8 0
3 years ago
What is a correct expression of the law of conservation mass
nekit [7.7K]
Law of conservation of mass- The total mass after a chemical reaction is exactly the same as the mass before.
5 0
3 years ago
Why are different units of measurement used for distances in space
AlexFokin [52]

Not all units of measurement are equal, but the value of each unit is used for its intended purpose, so we have different units of measurement for each problem.

7 0
3 years ago
34 atoms of carbon (C) react with 22 molecules of hydrogen gas (H2). How many molecules of methane (CH4) will be formed, and wha
kolbaska11 [484]

Answer:

11 molecules of CH4.

23 atoms of C is the leftover.

Explanation:

Hello!

In this case, for the formation of methane:

C+2H_2\rightarrow CH_4

We can see there is an excess of carbon based on their stoichiometry, because the needed amount of hydrogen gas molecules would be:

molecules _{H_2}=34atomC*\frac{2molec\ H_2}{1atomC} =68molec\ H_2

Thus, the formed molecules of methane are computed below:

molec\ CH_4=22molec\ H_2 *\frac{1molec\ CH_4}{2molmolec\ H_2} \\\\molec\ CH_4=11molec\ CH_4

In such a way, the leftover of carbon atoms are:

atoms \ C^{left over}=34-22molec\ H_2*\frac{1atoms C}{2molec\ H_2} \\\\atoms \ C^{left over}=23 atoms C

Best regards!

4 0
2 years ago
What will happen if you add more solute to a saturated solution?
Annette [7]
No more solute will dissolve at that temperature, the temperature would have to be increased in order for more solute to dissolve.
4 0
3 years ago
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