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OLEGan [10]
3 years ago
8

Please help me with this! I’ll mark you brainiest if it’s correct. I do know it’s either A or C

Chemistry
2 answers:
8090 [49]3 years ago
8 0
It is A
I only know that Lithium does not have Roman numerals after it only certain elements do so yea!
Volgvan3 years ago
6 0

Answer:

the correct answer is A

Explanation:

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<u>Answer:</u> The mass percent of lead in lead (IV) carbonate is 63.32 %

<u>Explanation:</u>

The given chemical formula of lead (IV) carbonate is Pb(CO_3)_2

To calculate the mass percentage of lead in lead (IV) carbonate, we use the equation:

\text{Mass percent of lead}=\frac{\text{Mass of lead}}{\text{Mass of lead (IV) carbonate}}\times 100

Mass of lead = (1 × 207.2) = 207.2 g

Mass of lead (IV) carbonate = [(1 × 207.2) + (2 × 12) + (6 × 16)] = 327.2 g

Putting values in above equation, we get:

\text{Mass percent of lead}=\frac{207.2g}{327.2g}\times 0100=63.32\%

Hence, the mass percent of lead in lead (IV) carbonate is 63.32 %

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