Answer:
11.1d + 3.2h - 15
Step-by-step explanation:
Answer:
x+17
Step-by-step explanation:
x + 17 is the answer
Answer:
a) Average velocity at 0.1 s is 696 ft/s.
b) Average velocity at 0.01 s is 7536 ft/s.
c) Average velocity at 0.001 s is 75936 ft/s.
Step-by-step explanation:
Given : If a ball is thrown straight up into the air with an initial velocity of 70 ft/s, its height in feet after t seconds is given by
.
To find : The average velocity for the time period beginning when t = 2 and lasting. a. 0.1 s.
, b. 0.01 s.
, c. 0.001 s.
Solution :
a) The average velocity for the time period beginning when t = 2 and lasting 0.1 s.





b) The average velocity for the time period beginning when t = 2 and lasting 0.01 s.





c) The average velocity for the time period beginning when t = 2 and lasting 0.001 s.




Answer:
Option 4
The answer is 10.8
Step-by-step explanation:
5/6 = 9/c
5c = 9 × 6
5c = 54
5c/5 = 54/5
c = 10.8
Thus, The value of c is 10.8
<h3>
<u>For </u><u>Verification</u>;</h3>
5/6 = 9/c
5/6 = 9/10.8
0.833 = 0.833
Hence, L.H.S = R.H.S
<u>-TheUnknownScientist</u><u> 72</u>