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sammy [17]
3 years ago
12

how much energy is transferred when 1 gm of boiling water at 100 degree celcius condenses to water at 100 degree celcius?

Physics
2 answers:
Mademuasel [1]3 years ago
6 0
The latent heat of vaporization for water is 2257 KJ per Kg . I'm pretty sure that's exactly the same as 2257 joules per gram. So ... When 1 gm of STEAM at 100 C condenses to 1 gm of liquid water at 100 C, it releases 2257 joules of heat energy to its environment.
deff fn [24]3 years ago
4 0
22.5 x 10 to the power 5 kilo/joules energy is transferred when boiling water at 100 degree celcius condenses to water at 100 degree celcius
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An amino acid mixture consisting of lysine, leucine, and glutamic acid is to be separated ion exchange chromatography using a ca
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Explanation:

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You have a closed milk container filled with air. If you were to put the closed milk jug in the freezer, which of the following
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3 years ago
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Which is an example of a chemical reaction ?
julia-pushkina [17]

Answer:

paper burned and turned into smoke...

Explanation:

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8 0
4 years ago
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An arrow of 43 g moving at 84 m/s to the right, strikes an apple at rest. The arrow sticks to the apple and both travel at 16.8
Aloiza [94]

Answer:

<em>The mass of the apple is 0.172 kg (172 g)</em>

Explanation:

<u>The Law Of Conservation Of Linear Momentum </u>

The total momentum of a system of bodies is conserved unless an external force is applied to it. The formula for the momentum of a body with mass m and speed v is  

P=mv.  

If we have a system of two bodies, then the total momentum is the sum of both momentums:

P=m_1v_1+m_2v_2

If a collision occurs and the velocities change to v', the final momentum is:

P'=m_1v'_1+m_2v'_2

Since the total momentum is conserved, then:

P = P'

Or, equivalently:

m_1v_1+m_2v_2=m_1v'_1+m_2v'_2

If both masses stick together after the collision at a common speed v', then:

m_1v_1+m_2v_2=(m_1+m_2)v'

We are given the mass of an arrow m1=43 g = 0.043 kg traveling at v1=84 m/s to the right (positive direction). It strikes an apple of unknown mass m2 originally at rest (v2=0). The common speed after they collide is v'=16.8 m/s.

We need to solve the last equation for m2:

m_2v_2-m_2v'=m_1v'-m_1v_1

Factoring m2 and m1:

m_2(v_2-v')=m_1(v'-v_1)

Solving:

\displaystyle m_2=\frac{m_1(v'-v_1)}{v_2-v'}

Substituting:

\displaystyle m_2=\frac{0.043(16.8-84)}{0-16.8}

\displaystyle m_2=\frac{-2.8896}{-16.8}

\displaystyle m_2=0.172\ kg

The mass of the apple is 0.172 kg (172 g)

3 0
3 years ago
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