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zimovet [89]
3 years ago
6

The the weight of an object is the same as the mass of an object

Physics
1 answer:
DIA [1.3K]3 years ago
5 0
Weight is the force exerted by the earth on a mass therefore weight = mass * acceleration due to gravity . Weight will different on different surfaces such as the moon ,earth etc . But mass is always the same regardless of the force exerted by the surface
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How do you find average velocity (average) from acceleration) and time (t)?
Tasya [4]

Average velocity is defined as the ratio in change in position to change in time,

v[ave] = ∆x/∆t

which on its own doesn't have anything to do with acceleration.

<u>If acceleration is constant</u>, the average velocity is the literal average of the initial and final velocities,

v[ave] = (v[final] + v[initial]) / 2

If this constant acceleration has magnitude a, the final velocity can be expressed in terms of the initial velocity by

v[final] = v[initial] + a*t

and plugging this into the previous equation gives

v[ave] = (v[initial] + a*t + v[initial])/2

v[ave] = v[initial] + 1/2*a*t

If the body in consideration is <u>initially at rest</u>, then

v[ave] = 1/2*a*t

which might be the relation you're looking for. But bear in mind the conditions I've underlined.

<u>If acceleration is not constant and changes over time</u>, so that the acceleration is some function of time a(t), then you can determine the velocity function v(t) by using the fundamental theorem of calculus. You need to know a particular velocity for some time to completely characterize v(t), though. For example, if you're given the initial velocity v[initial] = v(0), then

\displaystyle v(t) = v(0) + \int_0^t a(u) \, du

or if you know any other velocity for some time t₀ > 0,

\displaystyle v(t) = v(t_0) + \int_{t_0}^t a(u) \, du

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Answer:

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Explanation:

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Answer:

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Explanation:

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