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cupoosta [38]
2 years ago
15

In the spectrum of a galaxy that is travelling away from Earth a hydrogen line is observed to be shifted from 394 nm to 450 nm.

Calculate the velocity of recession of the galaxy.
Physics
1 answer:
Murljashka [212]2 years ago
3 0

The velocity of recession of the galaxy will be 37.3×10⁶ m/sec. The concept of Doppler effect is employed in the given problem.

<h3>What is the Doppler effect?</h3>

A sudden change in the frequency due to the distance between the objects and source is explained by the Doppler effect.

As the source and observer travel toward each other, the frequency of sound, light, or other waves increases or decreases.

A passing siren's rapid change in pitch, as well as astronomers' redshift, are both caused by this phenomenon.

Applications of the Doppler effect;

The rest wavelength is,\rm \lambda_0 = 394 \  nm

The distant wavelength is,\rm \lambda = 450 \ nm

The velocity of recession  is,V

The recession velocity is found as;

\rm V = (1-\frac{\lambda}{\lambda_0} )C \\\\ \rm V = (1-\frac{394}{450} )\times 3 \times 10^8  \\\\ V = (1- 0.875)\times 3 \times 10^8 \\\\ V = 37.3  \times 10^6  \ m/sec

Hence, the velocity of recession of the galaxy will be 37.3×10⁶ m/sec.

To learn more about the Doppler effect, refer to the link;

brainly.com/question/15318474

#SPJ1

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A charge 3q is at the origin, and a charge −2q is on the positive x axis at x=a. part a where on the x-axis would you place a th
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Answer:

x = a + \frac{a\sqrt2}{\sqrt3 - \sqrt2}

Explanation:

Position of charge 3q is x = 0

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so here we know that

when two charges are of opposite nature then the electric field will be zero on the line joining the two charges at the position near to smaller magnitude charge

So here the electric field will be zero if the field due to 3q is counterbalanced by field due to -2q

so here we can say

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\frac{r+a}{r} = \sqrt{\frac{3}{2}}

1 + \frac{a}{r} =\sqrt{\frac{3}{2}}

\frac{a}{r} = \frac{\sqrt3 - \sqrt2}{\sqrt2}

so we will have

r = \frac{a\sqrt2}{\sqrt3 - \sqrt2}

so the x coordinate of this position is given as

x = a + \frac{a\sqrt2}{\sqrt3 - \sqrt2}

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