Important: 35x2 12x − 36 is not an equation; to obtain an equation, you must set <span>35x2 12x − 36 = to 0:
</span><span>35x^2 + 12x − 36 = 0. Also, "the square of x" must be represented by "x^2," and you must insert either the + or the - sign in front of the term 12x.
I am assuming that you meant </span>35x^2 + 12x − 36 = 0.
If that is indeed the case, then a = 35, b = 12 and c = -36
and the discriminant is b^2 - 4ac, or (12)^2 - 4(35)(-36) = 5184.
Since the discriminant is positive, this equation has 2 real, unequal solutions. They are
-12 plus or minus sqrt(5184)
x = -----------------------------------------
2(35)
Answer:
The test statistic Z = 3.125
Step-by-step explanation:
<em>Given Population proportion P = 0.25</em>
<em>Given sample size 'n' = 696</em>
<em>Sample proportion 'p⁻' = 0.30</em>
Test statistic
<u><em>Final answer</em></u>:-
The test statistic Z = 3.125
Answer:
No, the on-time rate of 74% is not correct.
Solution:
As per the question:
Sample size, n = 60
The proportion of the population, P' = 74% = 0.74
q' = 1 - 0.74 = 0.26
We need to find the probability that out of 60 trains, 38 or lesser trains arrive on time.
Now,
The proportion of the given sample, p = 
Therefore, the probability is given by:
![P(p\leq 0.634) = [\frac{p - P'}{\sqrt{\frac{P'q'}{n}}}]\leq [\frac{0.634 - 0.74}{\sqrt{\frac{0.74\times 0.26}{60}}}]](https://tex.z-dn.net/?f=P%28p%5Cleq%200.634%29%20%3D%20%5B%5Cfrac%7Bp%20-%20P%27%7D%7B%5Csqrt%7B%5Cfrac%7BP%27q%27%7D%7Bn%7D%7D%7D%5D%5Cleq%20%5B%5Cfrac%7B0.634%20-%200.74%7D%7B%5Csqrt%7B%5Cfrac%7B0.74%5Ctimes%200.26%7D%7B60%7D%7D%7D%5D)
P![(p\leq 0.634) = P[z\leq -1.87188]](https://tex.z-dn.net/?f=%28p%5Cleq%200.634%29%20%3D%20P%5Bz%5Cleq%20-1.87188%5D)
P![(p\leq 0.634) = P[z\leq -1.87] = 0.0298](https://tex.z-dn.net/?f=%28p%5Cleq%200.634%29%20%3D%20P%5Bz%5Cleq%20-1.87%5D%20%3D%200.0298)
Therefore, Probability of the 38 or lesser trains out of 60 trains to be on time is 0.0298 or 2.98 %
Thus the on-time rate of 74% is incorrect.
<span><span><span><span><span><span><span><span><span><span><span><span>(</span></span><span><span><span><span><span><span>1</span></span><span><span>⋅</span></span><span><span>3</span></span></span><span><span>+</span></span><span><span><span>1</span></span><span><span><span>(</span></span><span><span><span><span>5</span></span><span><span>i</span></span></span></span><span><span>)</span></span></span></span></span><span><span><span><span><span>−</span></span><span><span>2</span></span></span><span><span>i</span></span></span><span><span><span>(</span></span><span><span><span><span>3</span></span><span><span>+</span></span><span><span><span>5</span></span><span><span>i</span></span></span></span></span><span><span>)</span></span></span></span></span></span><span><span>)</span></span></span><span><span><span>(</span></span><span><span><span><span>3</span></span><span><span><span>−</span></span><span><span>i</span></span></span></span></span><span><span>)</span></span></span></span></span></span><span><span><span><span>5</span></span></span></span><span /></span><span /></span></span></span></span></span><span>1⋅3+15i-2i3+5i3-i5</span>
