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Arturiano [62]
4 years ago
14

In Hooke’s law, what does the x represent?

Physics
1 answer:
Mice21 [21]4 years ago
6 0

Answer:   C

X = Displacement of the spring

Hooke's law: It states that the applied force F is proportional to the  displacement of spring .

            F ∝ x

            Where, x = displacement of spring in meters

                         F = force, measured in Newtons

In another words The force F is equal to the constant K times the disparagement.

            F = k.x

            Where k is constant and it depends on elastic material.

            Spring has restorative force.  

If the spring moves in opposite direction then,

           F = - k.x

A negative sign indicates that the spring resists and force is to the left. The compression of the spring is greater than the restoring force.  

   Example: A mass 'm' stretches a spring at a displacement x.    

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This procces is called evaporation.

Explanation:

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Name three ways that being obese puts a strain on your heart & can lead to serious health problems.
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3 0
3 years ago
Read 2 more answers
Determine whether the center of mass of the system consisting of the earth and moon lies inside or outside the earth. Assume tha
tester [92]

Answer:

R_cm = 4.66 10⁶ m

Explanation:

The important concept of mass center defined by

         R_cm = 1 / M   ∑  x_i m_i

where M is the total mass, x_i and m_i are the position and masses of each body

Let's apply this expression to our case.

Let's set a reference frame where the axis points from the center of the Earth to the Moon,

       R_cm = 1 / M (m_earth 0 + m_moon d)

the total mass is

      M = m_earth + m_moon

     

the distance from the Earth is zero because all mass can be considered to be at its gravimetric center

let's calculate

      M = 5.98 10²⁴ + 7.35 10²²

      M = 6.0535 10₂⁴24 kg

we substitute

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4 0
3 years ago
How much kinetic energy does a moving 100 kg object have if it is moving at 5 m/s?
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Answer:

The object has 1250 Joules of Kinetic Energy.

Explanation:

Kinetic Energy = \frac{1}{2}mass*velocity²

KE = \frac{1}{2}mv²

KE = \frac{1}{2}(100kg)(5m/s)²

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KE = 1250\frac{kg}{m/s^2}

KE = 1250J

4 0
3 years ago
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