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3 years ago

15

A 4.0 kg box is pressed into a spring. The spring constant is k=220 n/m. The box is released at the bottom of a frictionless ram

p and rises to a height of y=0.75m

1 answer:

VikaD [51]3 years ago

4 0

What’s the question, exactly? I’d be happy to help :)

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Which food chain shows the correct flow of energy is an ecosystem ?

Hitman42 [59]

The 4th one is correct
it starts from the sun then hay then rabbit then eagle

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4 years ago

Read 2 more answers

Two bicycle tires are set rolling with the same initial speed of 4.00 m/s along a long, straight road, and the distance each tra

77julia77 [94]

Answer:

The coefficient of rolling friction for the tire under low pressure is 0.0342.

Explanation:

Two bicycle tires are set rolling with the same initial speed of 4.00 m/s

Final speed of both the bicycle, speed is reduced by half is measured, v = 2 m/s.

Here,

$u_kmg = ma\\\\a=\mu g$

Using third equation of motion as :

$v^2-u^2=2as\\\\v^2-u^2=2\mu gs\\\\\mu =\dfrac{v^2-u^2}{2gs}\\\\\mu =\dfrac{4^2-2^2}{2\times 9.8\times 17.9}\\\\\mu=0.0342$

So, the coefficient of rolling friction for the tire under low pressure is 0.0342.

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3 years ago

Two waves are shown below. When the crest of wave A meets the crest of wave B, ____________ interference will occur.

Lana71 [14]

Answer: The Answer: Destructive

Explanation: hope This helped

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3 years ago

A blue car with mass mc = 427 kg is moving east with a speed of vc = 20 m/s and collides with a purple truck with mass mt = 1282

polet [3.4K]

Answer:8540 kg-g/s

Explanation:

Given

mass of blue car $m_c=427 kg$

velocity of blue car $v_c=20 m/s$

mass of the truck $m_t=1282 kg$

speed of truck $v_t=13 m/s$

After collision they stick and lock together

Let v be the velocity of combined system at angle \theta from vertical

Conserving momentum in east direction

$m_c\times v_c=(m_c+m_t)v\cos \theta$

$427\times 20 =1709\times v\cos \theta$ ------1

Conserving Momentum in Y direction

$m_t\times v_t=(m_c+m_t)v\sin \theta$

$1282\times 13 =1709\times v\sin \theta$ -------2

squaring and then adding 1 & 2 we get

$(8540)^2+(16666)^2=(1709)^2\cdot v^2$

v=10.95 m/s

initial momentum of car $=427\times 20=8540 kg-m/s$

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4 years ago

Which is not an example of how an object gains elastic potential energy by stretching?

lora16 [44]

C because you don’t put a force of which you choose and the force wouldn’t be strong enough

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4 years ago