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3 years ago

What are the different isotopes

Physics

1 answer:

Norma-Jean [14]3 years ago

6 0

Answer:

Isotopes can both be the same element but have a different number of electrons

Explanation: not sure if more was supposed to be there, but i tried

You might be interested in

When electrons are moving we call it _______

agasfer [191]

It *can* be called "Dynamic Electricity".

Hope that helps a little bit XD.

5 0

3 years ago

Suppose that an object in free fall were somehow equipped with a speedometer. by how much would its speed readings increase with

alina1380 [7]

The speed would increase by however much the acceleration due to gravity is. On earth, I believe that is 32ft/s or 9.8m/s

5 0

4 years ago

An electric turntable 0.730 mm in diameter is rotating about a fixed axis with an initial angular velocity of 0.240 rev/srev/s a

Zolol [24]

Answer:

a) $\omega = 0.421\,\frac{rev}{s}$ , b) $\Delta \theta = 0.066\,rev$ , c) $v = 0.966\,\frac{mm}{s}$ , d) $a = 3.293\,\frac{mm}{s^{2}}$

Explanation:

a) The angular velocity of the turntable after $0.200\,s$ .

$\omega = \omega_{o} + \alpha\cdot \Delta t$

$\omega = 0.240\,\frac{rev}{s} + (0.906\,\frac{rev}{s^{2}} )\cdot (0.2\,s)$

$\omega = 0.421\,\frac{rev}{s}$

b) The change in angular position is:

$\Delta \theta = \omega_{o}\cdot t + \frac{1}{2} \cdot \alpha \cdot t^{2}$

$\Delta \theta = (0.240\,\frac{rev}{s} )\cdot (0.2\,s) + \frac{1}{2}\cdot (0.906\,\frac{rev}{s^{2}} )\cdot (0.2\,s)^{2}$

$\Delta \theta = 0.066\,rev$

c) The tangential speed of a point on the rim of the turn-table:

$v = r\cdot \omega$

$v = (0.365\times 10^{-3}\,m)\cdot (0.421\,\frac{rev}{s} )\cdot (\frac{2\pi\,rad}{1\,rev} )$

$v = 9.655\times 10^{-4}\,\frac{m}{s}$

$v = 0.966\,\frac{mm}{s}$

d) The tangential and normal components of the acceleration of the turn-table:

$a_{t} = (0.365\times 10^{-3}\,m)\cdot (0.906\,\frac{rev}{s^{2}})\cdot (\frac{2\pi\,rad}{1\,rev} )$

$a_{t} = 2.078\times 10^{-3}\,\frac{m}{s^{2}}$

$a_{t} = 2.078\,\frac{mm}{s}$

$a_{n} = (0.365\times 10^{-3}\,m)\cdot \left[(0.421\,\frac{rev}{s} )\cdot (\frac{2\pi\,rad}{1\,rev} )\right]^{2}$

$a_{n} = 2.554\times 10^{-3}\,\frac{m}{s^{2}}$

$a_{n} = 2.554\,\frac{mm}{s^{2}}$

The magnitude of the resultant acceleration is:

$a = \sqrt{(2.078\,\frac{mm}{s} )^{2}+(2.554\,\frac{mm}{s} )^{2}}$

$a = 3.293\,\frac{mm}{s^{2}}$

8 0

3 years ago

If you hit a wall, will the force that you exert on the wall be greater than, or less than, or equal to the force that the wall

leva [86]

I think this would have to be equal because the wall is not moving away from or into your hit so therefore your force is just as equal as the walls force

5 0

3 years ago

One light-year is the distance light travels in one year. This distance is equal to 9.461 1015 m. After the sun, the star neares

Oliga [24]

Answer:

A.) 411.6 Mega metres

B.) 411.6 × 10^18 Picometers

Explanation:

Given that One light-year is the distance light travels in one year. This distance is equal to 9461 1015 m.

After the sun, the star nearest to Earth is Alpha Centauri, which is about 4.35 light-years from Earth.

The distance travelled will be

Distance = 9461 1015 × 4.35

Distance = 411557915.3 m

To Express this distance in

a. megameters, divide the value by 1000000

411557915.3 / 1000000

411.5579153 Mega metre

411.6 Mega metres approximately

b. picometers, multiply by 10^12

That is, 411557915.3 × 10^12

411.6 × 10^18 Picometers

4 0

4 years ago