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cupoosta [38]
3 years ago
12

When lithium reacts with bromine to form th. Compound LiBr, each lithium atom gains one electron and becomes a negatively charge

d ion Games three electrons and becomes a negatively charged ion it loses one electron in becomes a positively charged ion loses three electrons and becomes a positively charged ion
Chemistry
1 answer:
Svetradugi [14.3K]3 years ago
7 0
What is your question? i dont get it 
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What isotope is the product of the alpha (*2He) nuclear decay of Radon-222 (222U)?
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Answer:

ⁿₐX => ²¹⁸₈₄Po

Explanation:

Let ⁿₐX be the isotope.

Thus, the equation can be written as follow:

²²²₈₆Rn —> ⁴₂α + ⁿₐX

Next, we shall determine the value of 'n' and 'a'. This can be obtained as follow:

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ⁿₐX => ²¹⁸₈₄Po

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²²²₈₆Rn —> ⁴₂α + ²¹⁸₈₄Po

3 0
3 years ago
What is the ratio of [a–]/[ha] at ph 2.75? the pka of formic acid (methanoic acid, h–cooh) is 3.75?
Varvara68 [4.7K]

The dissociation of formic acid is:

HCOOH \rightleftharpoons HCOO^{-} + H^{+}

The acid dissociation constant of formic acid, k_a is:

k_a = \frac{[HCOO^{-}]  [H^{+}]}{HCOOH}

Rearranging the equation:

\frac{[HCOO^{-}]}{[HCOOH]} = \frac{k_a}{[H_+]}

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Substituting the values in the equation:

\frac{[HCOO^{-}]}{[HCOOH]} = \frac{k_a}{[H_+]}

\frac{[HCOO^{-}]}{[HCOOH]} = \frac{1.78\times 10^{-4}}{1.78\times 10^{-3}}

Hence, the ratio is \frac{1}{10}.

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l

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