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Oduvanchick [21]
3 years ago
10

Can someone please explain to me how to do this and help me?​ ASAP too!!​

Mathematics
1 answer:
Olin [163]3 years ago
3 0

So, the time is the Y axis and the speed is the X axis graph the times and the speed and fill in the boxes with the time and speed.

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Amy and Stephanie were playing a number game. Amy picked a number and told Stephanie that if she added 9 to the number and multi
____ [38]

Answer:

Step-by-step explanation:

B

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3 years ago
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A family is driving 600 miles. Assuming they stop to get gas 3 times and eat 2 times, how many hours will it take them to reach
Umnica [9.8K]
Lets assume that they are driving at an average of 70mph, and getting gas takes 10 minutes, and stopping to eat takes 30.

t=d/s

t=600/70
t=8.57 

Stopping to eat twice is 30 x 2 = 60 (another hour)

and Gas is 10 x 3 = 30 minutes (0.5 hours)

Total time is,

8.57+1+0.5 =10.07

So the trip will take approx 10.7 hours total.

(This is using my assumptions, from my experience!)


8 0
3 years ago
Help friends please :(
olga nikolaevna [1]
The correct answer is:  [B]:  " 2⁶  *  2^(3/10)  *  2^(8/100) " .
________________________________________________________

7 0
3 years ago
In the accompanying diagram of parallelogram ABCD,diagonals AC and DB intersect at E, AE = 3x - 4, andEC = x + 12.What is the va
skelet666 [1.2K]

x = 8

Explanation:

AE = 3x - 4

EC = x + 12

SInce diagonals AC and DB intersect at E

it means the lines which meet at the intersection E are equal. A and C meet at E which gives AE and EC

AE = EC

3x - 4 = x + 12

collect like terms:

3x - x = 12 + 4

2x = 16

divide both sides by 2:

2x/2 = 16/2

x = 8

4 0
1 year ago
HELP PLEASE!! I DONT UNDERSTAND!!!!!!!!!! THANKS SO MUCH
8090 [49]

Hello, please consider the following.

We will multiply the numerator and denominator by

4+\sqrt{6x}

to get rid of the root in the denominator.

First of all, we cannot divide by 0, right? So, we need to make sure that the denominator is different from 0.

4-\sqrt{6x} =0\sqrt{6x}=4\\\\\text{Take the square}\\\\6x=4^2=16\\\\x=\dfrac{16}{6}=\dfrac{8}{3}

We need to take any x real number different from 8/3 then and simplify the expression.

Let's do it!

\begin{aligned}\dfrac{4}{4-\sqrt{6x}}&=\dfrac{4(4+\sqrt{6x})}{(4+\sqrt{6x})(4-\sqrt{6x})}\\\\&=\dfrac{4(4+\sqrt{6x})}{(4^2-\sqrt{6x}^2)}\\\\&=\dfrac{4(4+\sqrt{6x})}{(16-6x)}\\\\&=\dfrac{2(4+\sqrt{6x})}{(8-3x)}\\\\&\large \boxed{=\dfrac{8+2\sqrt{6x}}{8-3x}}\end{aligned}

Thank you

8 0
3 years ago
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