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gulaghasi [49]
3 years ago
15

A trapezoid has a perimeter of 117cm. The two shortest sides have the same length. The third side is 12 cm longer than one short

side. The final side is 9cm less than three times one short side. How long is each side of the Trapezoid?
Pls pls help I need an answer, I have to finish this in 15 mins, this is really hard and I will give you 30 points :)
Mathematics
1 answer:
Murljashka [212]3 years ago
3 0
Let the short side be x.
2x+(x+12)+(3x-9)=117
6x-3=117
6x=120
x=120/6=20
Each of the short sides is 20, the third side is 32, and the last side is 51. Hope this helped!
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A+b=21 b+c=24 c+d=32 d+e=37 e+f=31 f+g=25 g+a=26 find a,b,c,d,e,f,g,
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Answer:

a = 12

b = 9

c = 15

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Step-by-step explanation:

Given that

(a + b) = 21 ...... (1)

(b + c) = 24 ........ (2)

(c + d) = 32 ........ (3)

(d + e) = 37 ........ (4)

(e + f) = 31 .......... (5)

(f + g) = 25 ........ (6)

(g + a) = 26 ......... (7)

Hence, adding all the equations we get, 2(a + b + c + d + e + f + g) = 196

⇒ (a + b + c + d + e + f + g) = 98 ...... (8)

Adding equations (2), (4) and (6), we get (b + c + d + e + f + g) = 86.

Therefore, from equation (8), we get a = 98 - 86 = 12 (Answer)

Adding equations (3), (5), and (7) we get,

a + c + d + e + f + g = 89

Hence, from equation (8), we have b = 98 - 89 = 9 (Answer)

Similarly, adding equations (1), (4), and (6) we get,

a + b + d + e + f + g = 83,

Hence, c = 98 - 83 = 15 (Answer)

Now, adding equations (2), (5) and (7), we get

a + b + c + e + f + g = 81. Hence, d = 98 -81 = 17 (Answer)

Adding equations (1), (3), and (6)

a + b + c + d + f + g = 78. Hence e = 98 - 78 = 20 (Answer)

Adding equations (2), (4), and (7)

a + b + c + d + e + g = 87. Hence f = 98 - 87 = 11 (Answer)

Adding equations (1), (3), and (5)

a + b + c + d + e + f = 84. Hence g = 98 - 84 = 14 (Answer)

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Step-by-step explanation:

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