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3 years ago

14

Only for people who know the answer to this question fully can answer this others please leave this question.So, Variation is ca

used by what two factors...????
PLEASE ANSWER IF YOU KNOW 100% TO THE ANSWER OF THIS QUESTION ...Thanks

2 answers:

Julli [10]3 years ago

6 0

Can you please specify which type of variation you are looking for?

Vikki [24]3 years ago

3 0

Answer:

Please elaborate which variation. There are different types of variation

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When electrons are shared, the type of bonding is called _____.

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It's called covelant bonding

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A ball having mass 2 kg is connected by a string of length 2 m to a pivot point and held in place in a vertical position. A cons

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Complete Question

A ball having mass 2 kg is connected by a string of length 2 m to a pivot point and held in place in a vertical position. A constant wind force of magnitude 13.2 N blows from left to right. Pivot Pivot F F (a) (b) H m m L L If the mass is released from the vertical position, what maximum height above its initial position will it attain? Assume that the string does not break in the process. The acceleration of gravity is 9.8 m/s 2 . Answer in units of m.What will be the equilibrium height of the mass?

Answer:

$H_m=1.65m$

$H_E=1.16307m$

Explanation:

From the question we are told that

Mass of ball $M=2kg$

Length of string $L= 2m$

Wind force $F=13.2N$

Generally the equation for $\angle \theta$ is mathematically given as

$tan\theta=\frac{F}{mg}$

$\theta=tan^-^1\frac{F}{mg}$

$\theta=tan^-^1\frac{13.2}{2*2}$

$\theta=73.14\textdegree$

Max angle = $2*\theta= 2*73.14=>146.28\textdegree$

Generally the equation for max Height $H_m$ is mathematically given as

$H_m=L(1-cos146.28)$

$H_m=0.9(1+0.8318)$

$H_m=1.65m$

Generally the equation for Equilibrium Height $H_E$ is mathematically given as

$H_E=L(1-cos73.14)$

$H_E=0.9(1+0.2923)$

$H_E=1.16307m$

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3 years ago

How efficient are the small and large scale solar-power systems used in individual homes and industrial settings? What is the en

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$\color{Blue}\huge\boxed{Answer}$

<em>The potential environmental impacts associated with solar power—land use and habitat loss, water use, and the use of hazardous materials in manufacturing—can vary greatly depending on the technology, which includes two broad categories: photovoltaic (PV) solar cells or concentrating solar thermal plants (CSP).</em>

Explanation:

I just answer the second question

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3 years ago

Which of the following situations would violate the second law of

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Answer:

c

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3 years ago

A 31 kg block is initially at rest on a horizontal surface. A horizontal force of 83 N is required to set the block in motion. A

Hatshy [7]

Answer:

The static and kinetic coefficients of friction are 0.273 and 0.181, respectively.

Explanation:

By Newton's Laws of Motion and definition of maximum friction force, we derive the following two formulas for the static and kinetic coefficients of friction:

$\mu_{s} = \frac{f_{s}}{m\cdot g}$ (1)

$\mu_{k} = \frac{f_{k}}{m\cdot g}$ (2)

Where:

$\mu_{s}$ - Static coefficient of friction, no unit.

$\mu_{k}$ - Kinetic coefficient of friction, no unit.

$f_{s}$ - Static friction force, in newtons.

$f_{k}$ - Kinetic friction force, in newtons.

$m$ - Mass, in kilograms.

$g$ - Gravitational constant, in meters per square second.

If we know that $f_{s} = 83\,N$ , $f_{k} = 55\,N$ , $m = 31\,kg$ and $g = 9.807\,\frac{m}{s^{2}}$ , then the coefficients of friction are, respectively:

$\mu_{s} = \frac{83\,N}{(31\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)}$

$\mu_{s} = 0.273$

$\mu_{k} = \frac{55\,N}{(31\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)}$

$\mu_{k} = 0.181$

The static and kinetic coefficients of friction are 0.273 and 0.181, respectively.

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3 years ago