Question

An electron in an x-ray machine is accelerated through a potential difference of 1.00 × 104 v before it hits the target. What is the kinetic energy of the electron in electron volts?

Answer 1

Kinetic energy of electron is gained by the potential energy that it is getting through the potential applied across it

now here we know that that

$V = 1.00 \times 10^4 Volts$

charge that is accelerated is an electron

so we will have

$U = qV$

here we know that

$q = 1e$

$U = (e)(1.00 \times 10^4 V)$

$U = 1.00 \times 10^4 eV$

so kinetic energy will be same as potential energy which is equal to

$KE = 1.00 \times 10^4 eV$