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GrogVix [38]
3 years ago
11

A box collides with a ball as shown in the diagram below. After the collision, what

Physics
1 answer:
azamat3 years ago
8 0

The final momentum of the ball after collision is 13 kg.m/s.

The given parameters;

  • <em>initial momentum of the box, P₁ = 15 kg.m/s</em>
  • <em>initial momentum of the ball, P₂ = 3 kg.m/s</em>
  • <em>final momentum of the ball, P₃ = 5 kg.m/s</em>

Let the final momentum of the ball after collision = P₄

Apply the principle of conservation of linear momentum to determine the final momentum of the ball after collision;

total momentum before collision = total momentum after collision

P₁ + P₂ = P₃ + P₄

15 + 3 = 5 + P₄

18 = 5 + P₄

18 - 5 = P₄

13  = P₄

Thus, the final momentum of the ball after collision is 13 kg.m/s.

Learn more here:brainly.com/question/24424291

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Answer:

166 W

Explanation:

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\text{Power} = \dfrac{\text{Work done}}{\text{time}}

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The weight is the product of the mass and acceleration of gravity, <em>g</em>. Taking <em>g</em> as 9.81 m/s², the weight is

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4 0
3 years ago
A 740-kg boulder is raised from a quarry 119 m deep by a long uniform chain having a mass of 550 kg . This chain is of uniform s
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Answer:

A) the maximum acceleration the boulder can have and still get out of the quarry

B) how long does it take to be lifted out at maximum acceleration if it started from rest

Explanation:

A)

let +y is upward. look below at the free body diagram. the mass M refers to the combined mass of the boulder and chain.

the weight of the chain is:   w_{c} =m_{c} g   and maximum tension is T=2.50 m_{c} g=1.41*10^4N

total mass and weight is :

M =m_{c}+ m_{b} =740kg+550kg=1290 kg

w_{M} =1.2650*10^4N

∑F_{y} =ma_{y}

T-M_{g} =Ma_{y}

a_{y} =(t-M_{g} )/M=(2.50m_{c} -M_{g} )/M=(2.50.550kg-1290kg)(9.8m/s^2)/1290kg

=0.645m/s^2

B)

maximum acceleration

a_{y} =0.645m/s^2\\\\y-y_{0} =119m\\v_{0y} =0

using y-y_{0} =v_{oy} t+1/2(a_{y} )t^2

to solve for t

t=\sqrt{2(y-y_{0} )/a_{y} }

t=\sqrt{2(119m)/0.645m/s^2} =19.20s

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Name 2 different "limiting Factors" that limit the size of a population in a given ecosystem.
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if abus travelling at 20m/s is subject to steady decceleration of 5m/s².how long will it take yo come to rest.​
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Answer:

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