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ahrayia [7]
3 years ago
5

A network charges $855,000 for a 30-second ad during a major televised sports event. The advertisers must purchase a minimum of

three ads during the broadcast. If an advertiser buys the smallest number of ads possible, what is the advertiser's total cost?
Mathematics
1 answer:
blondinia [14]3 years ago
7 0
2,565,000 is the answer
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PLEASE HELP
Reil [10]
Is there a graph or anything given
6 0
3 years ago
The system of equations 2y = 14 - 2x and y=-x+ 7 is
elena-s [515]

Answer:

  • Infinitely many solutions

Step-by-step explanation:

<u>Given system:</u>

  • 2y = 14 - 2x
  • y = -x + 7

<u>Divide the first equation by 2 and rearrange:</u>

  • 2y/2 = 14/2 - 2x/2
  • y = 7 - x
  • y = -x + 7

We got the same equation with the second one. It means we have two of the same lines overlapping.

This gives us infinitely many solutions.

7 0
3 years ago
EXPERTS/ACE/GENIUSES PLZ HELP
Anna71 [15]
I believe it's 8 because it's scale is 4 times bigger.
2×4=8
6 0
3 years ago
Read 2 more answers
he one‑sample t statistic from a sample of n = 23 observations for the two‑sided test of H 0 : μ = 15 versus H α : μ &gt; 15 has
DedPeter [7]

Answer:

t = 2.24

The first step is calculate the degrees of freedom, on this case:  

df=n-1=23-1=22  

Since is a one side right tailed test the p value would be:  

p_v =P(t_{(22)}>2.24)=0.01776  

And for this case we can conclude that:

0.01 < p_v < 0.025

And we will reject the null hypothesis at \alpha=0.025 since p_v < \alpha

Step-by-step explanation:

Data given and notation  

\bar X represent the mean height for the sample  

s represent the sample standard deviation

n=23 sample size  

\mu_o =15 represent the value that we want to test

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is higher than 15, the system of hypothesis would be:  

Null hypothesis:\mu \leq 15  

Alternative hypothesis:\mu > 15  

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

For this case the statistic is given:

t = 2.24

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=23-1=22  

Since is a one side right tailed test the p value would be:  

p_v =P(t_{(22)}>2.24)=0.01776  

And for this case we can conclude that:

0.01 < p_v < 0.025

And we will reject the null hypothesis at \alpha=0.025 since p_v < \alpha

5 0
3 years ago
There are 6 boxes on a table. There are 30 crayons in each box. How many crayons are there in all?
sladkih [1.3K]

Answer:

180

Step-by-step explanation:

All you do is multiply 30 by 6!

7 0
3 years ago
Read 2 more answers
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