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ahrayia [7]
3 years ago
5

A network charges $855,000 for a 30-second ad during a major televised sports event. The advertisers must purchase a minimum of

three ads during the broadcast. If an advertiser buys the smallest number of ads possible, what is the advertiser's total cost?
Mathematics
1 answer:
blondinia [14]3 years ago
7 0
2,565,000 is the answer
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STatiana [176]
It’s the last one 7 sqrt5+8sqrt2/27
6 0
3 years ago
Kyle ran 200 yard in 40 sec. How many feet could she ran each sec ?
Ghella [55]
5 feet a second. and now i am just saying things because this website has to make me have 20 words
8 0
3 years ago
The midpoint of AB is M(-4,2). If the coordinates of A are (-6,5), what are the
-Dominant- [34]

Answer:

(-2,-1)

Step-by-step explanation:

Midpoints are found when you do ([x(subscript A) + x(subscript B)]/2, [y(subscript A) + y(subscript B)]. Therefore your equation (for x of B) should look like this:

-4 = ([-6+x]/2)

After you solve for x, you should have gotten -2 for x.

Then you do the same for y:

2 = ([5+y]/2)

You should get -1. Your final answer should be (-2, -1)

8 0
2 years ago
In a bolt factory, machines 1,2, and 3 respectively produce 20%, 30% and 50% of the total output. of their respective outputs 5%
lorasvet [3.4K]

Answer:

a. 1/10 or 10%

b. 1/2 or 50%

Step-by-step explanation:

Since the combination of machines 1, 2 and 3 produce 100% of the total output when added together, then the probability of choosing a bolt at random that is defective is: 5 + 2 + 3 = 10% out of 100% or 10/100, which is 1/10 or 10%.

If the bolt that is choosen at random is defective, than the probability that it came from machine 1 is 5/10 or 1/2 which is also 50%.

3 0
3 years ago
Evaluate the surface integral S F · dS for the given vector field F and the oriented surface S. In other words, find the flux of
slega [8]
 <span>Let r(x,y) = (x, y, 9 - x^2 - y^2) 

So, dr/dx x dr/dy = (2x, 2y, 1) 

So, integral(S) F * dS 
= integral(x in [0,1], y in [0,1]) (xy, y(9 - x^2 - y^2), x(9 - x^2 - y^2)) * (2x, 2y, 1) dy dx 
= integral(x in [0,1], y in [0,1]) (2x^2y + 18y^2 - 2x^2y^2 - 2y^4 + 9x - x^3 - xy^2) dy dx 
= integral(x in [0,1]) (x^2 + 6 - 2x^2/3 - 2/5 + 9x - x^3 - x/3) dx 
= integral(x in [0,1]) (28/5 + x^2/3 + 26x/3 - x^3) dx 
= 28/5 + 40/9 - 1/4 
= 1763/180 </span>
6 0
3 years ago
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