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sattari [20]
3 years ago
9

Find the other end point of the line segment that has the given points: Endpoint: (5,1) Midpoint: (9,3)

Mathematics
1 answer:
Tems11 [23]3 years ago
8 0
The formula for the midpoint of a line segment:
(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})
where x₁, y₁ - the coordinates of one endpoint; x₂, y₂ - the coordinates of the other endpoint

\hbox{endpoint} - (5,1) \\
x_1=5 \\ y_1=1 \\ \\ \hbox{midpoint} - (9,3) \\ \Downarrow \\ \frac{5+x_2}{2}=9 \\ 5+x_2=18 \\ x_2=13 \\ \\ \frac{1+y_2}{2}=3 \\ 1+y_2=6 \\ y_2=5 \\ \\
\hbox{the other endpoint} - \boxed{(13,5)}
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The object below is made of solid plastic. It is a cylinder with an indentation at the top in the shape of a cone. What is the v
Anastasy [175]

Answer:

97.6 cm³

Step-by-step explanation:

Volume of plastic object :

Volume of cylinder - volume of cone

From. The diagram. :

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Volume of cylinder = pi*r²h

V = 22/7 * 2² * 8 = 100.53096 cm³

Volume of cone = 1/3*pi*r²h

V = 1/3 * 22/7 * 2² * 8

V = 2.9321531 cm³

(100.53096 - 2.9321531) cm³

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5 0
3 years ago
What is 0.6 divided by 13.2
Romashka [77]

Answer:

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Step-by-step explanation:

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6 0
3 years ago
What is the product?
ZanzabumX [31]

Answer:

The product is:

\left[\begin{array}{cc}15 & 14\\-1 & 9\end{array}\right]

Step-by-step explanation:

For this problem you need to multiply the first row only for the two first column of the others matrix and get the desired result:

\left[\begin{array}{ccc}1&3&1\\-2&1&0\end{array}\right] \times \left[\begin{array}{cc}2&-2\\3&5\\4&1\end{array}\right]

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So the value of the element in the position a_{11} is 15

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So the value of the element in the position a_{12} is 14

Then with these two values you can determinate the result matrix.

\left[\begin{array}{cc}15 & 14\\-1 & 9\end{array}\right]

3 0
2 years ago
How would I do number<br> 5?
sukhopar [10]
N - 5 ≥ -2

5 - 5 ≥ -2 

5 - 5 = 0

n = 5

5 - 5 ≥ -2

5 - 5 = 0

(0 ≥ -2)
3 0
3 years ago
Tom has 7 more silver dollars than Jimmy. Together they have a total of 71 silver dollars. How many silver dollars does Tom have
Eddi Din [679]
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3 years ago
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