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inysia [295]
3 years ago
11

Ainda sobre a combustao completa do metanol que pode ser representada pela equação nao-balanceada abaixo. Quando se utilizam 8,0

mols de metanol nessa reação, qual é a quantidade de materia (mol) de agua produzida (em mols)?
(olhe a imagem por favor)

Chemistry
1 answer:
Radda [10]3 years ago
3 0

Answer:

n_{H_2O}=16molH_2O

Explanation:

Hello,

In this case, given the properly balanced reaction:

CH_3OH+\frac{3}{2} O_2\rightarrow CO_2+2H_2O

If 8.0 moles of methanol react, we can compute the produced grams of water by noticing the 1:2 molar ratio between them in the chemical reaction (stoichiometric coefficients):

n_{H_2O}=8molCH_3OH*\frac{2molH_2O}{1molCH_3OH} \\\\n_{H_2O}=16molH_2O

Best regards.

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