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inysia [295]
3 years ago
11

Ainda sobre a combustao completa do metanol que pode ser representada pela equação nao-balanceada abaixo. Quando se utilizam 8,0

mols de metanol nessa reação, qual é a quantidade de materia (mol) de agua produzida (em mols)?
(olhe a imagem por favor)

Chemistry
1 answer:
Radda [10]3 years ago
3 0

Answer:

n_{H_2O}=16molH_2O

Explanation:

Hello,

In this case, given the properly balanced reaction:

CH_3OH+\frac{3}{2} O_2\rightarrow CO_2+2H_2O

If 8.0 moles of methanol react, we can compute the produced grams of water by noticing the 1:2 molar ratio between them in the chemical reaction (stoichiometric coefficients):

n_{H_2O}=8molCH_3OH*\frac{2molH_2O}{1molCH_3OH} \\\\n_{H_2O}=16molH_2O

Best regards.

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A stock solution of ammonia in water is 28 wt% NH3. The Formal Weight (FW) of NH3 is 17.03 g/mol). The solution density at room
weqwewe [10]

Answer:

[NH₃] = 14.7 mol/L

Explanation:

28 wt% is a type of concentration that indicates that 28 g of ammonia is contained in 100 g of solution.

Let's determine the amount of ammonia:

28 g . 1 mol / 17.03g = 1.64 moles of NH₃

You need to consider that, when you have density's data it is always referred to solution:

Mass of solution is 100 g, let's find out the volume

0.90 g/mL = 100 g /V

V = 100 g / 0.90mL/g → 111.1 mL

We convert the volume to L → 111.1 mL . 1 L/1000mL = 0.1111 L

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mol/L = M → molarity a sort of concentration that indicates the moles of solute in 1L of solution

4 0
2 years ago
Since helium is lighter than air, it is difficult to measure the mass of a sample, so to find out the mass of helium in a birthd
d1i1m1o1n [39]

Answer:

0.7457 g is the mass of the helium gas.

Explanation:

Given:  

Pressure = 3.04 atm

Temperature = 25.0 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T₁ = (25.0 + 273.15) K = 298.15 K  

Volume = 1.50 L

Using ideal gas equation as:

PV=nRT

where,  

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 0.0821 L.atm/K.mol

Applying the equation as:

3.04 atm × 1.50 L = n × 0.0821 L.atm/K.mol × 298.15 K  

<u>⇒n = 0.1863 moles</u>

Molar mass of helium = 4.0026 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

0.1863\ mole= \frac{Mass}{4.0026\ g/mol}

Mass_{He}= 0.7457\ g

<u>0.7457 g is the mass of the helium gas. </u>

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I don’t know what exactly is but see at the picture.

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3 years ago
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Explanation: And that's how it goes, I hope you understood it well!

Best regards (Pr. El Haji)

6 0
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