Answer:
Explanation:
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In this case, according to the given information it turns out possible for us to realize that one mole of the given compound, Mg(ClO₄)₂, has one mole of Mg, two moles of Cl and eight moles of O; thus, we proceed as follows:
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<span>only D-glucose is found in disaccharides and polysaccharides.</span>
Answer:-
27.38%
Explanation:-
Molecular weight of sodium hydrogen carbonate NaHCO3
= 23 x 1 + 1 x 1 + 12 x 1 + 16 x 3
= 84 gram
Total sodium Na present in NaHCO3 = 23 x 1 = 23 gram
Percentage of sodium present=
Total sodium x 100/ (Total molecular weight)
= 23 x 100 / 84
= 27.38 %
The volume of one mole of substance is 22.4 L
D I believe peace out Hope this helps
