The value of x in the equation 1/2x = -1/2x when 4 is subtracted from both sides is 0(not defined)
Subtraction of fraction
Startfraction one-half EndFraction x equals negative StartFraction one-half EndFraction
1/2x = -1/2x
- Subtract 4 from both sides
1/2x - 4 = -1/2x - 4
(x-8) / 2 = (-x-8) / 2
(x - 8) / 2 = (-x-8) / 2
2(x - 8) = 2(-x - 8)
2x - 16 = -2x - 16
2x + 2x = -16 + 16
4x = 0
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Answer:I believe the answer is ab is equal to ba
Step-by-step explanation:
It looks like the equation is
-sin²(<em>x</em>) = cos(2<em>x</em>)
Recall the half-angle identity for sine:
sin²(<em>x</em>) = (1 - cos(2<em>x</em>))/2
Then the equation can be written as
-(1 - cos(2<em>x</em>))/2 = cos(2<em>x</em>)
Solve for cos(2<em>x</em>):
-1/2 + 1/2 cos(2<em>x</em>) = cos(2<em>x</em>)
-1/2 = 1/2 cos(2<em>x</em>)
cos(2<em>x</em>) = -1
On the unit circle, cos(<em>y</em>) = -1 when <em>y</em> = arccos(-1) = <em>π</em>. Since cosine has a period of 2<em>π</em>, more generally we have cos(<em>y</em>) = -1 for <em>y</em> = <em>π</em> + 2<em>nπ</em> where <em>n</em> is any integer. Then
2<em>x</em> = <em>π</em> + 2<em>nπ</em>
<em>x</em> = <em>π</em>/2 + <em>nπ</em>
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In the interval [-<em>π</em>, <em>π</em>], you get two solutions <em>x</em> = -<em>π</em>/2 and <em>x</em> = <em>π</em>/2.
