Question

Calculate the volume of 48.3 g of carbon monoxide at STP. Enter your answer in the box provided. L

Answer 1

Explanation:

STP means standard temperature and pressure where values are as follows.

                      T = 273.15 K,         P = 1 atm

According to ideal gas equation, PV = nRT. Since, it is given that mass is 48.3 g and we have to find the volume as follows.

                  n = $\frac{mass}{\text{molar mass}}$

So,                       PV = nRT

               V = $\frac{mass}{\text{molar mass}} \times \frac{RT}{P}$                  

                   = $\frac{48.3 g}{28 g/mol} \times \frac{0.0821 L atm/mol K \times 273.15 K}{1 atm}$             (molar mass of CO = 28 g/mol)

                   = 38.68 L                

Thus, we can conclude that volume of  48.3 g of carbon monoxide at STP is 38.68 L.