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2 years ago

14

Please answer for brainliest and if your answer is correct I'll give extra points. screenshot of the question is below.

2 answers:

ozzi2 years ago

8 0

Concentration - 3

Phase - 1

Catalyst - 4

Surface area - 2

Alik [6]2 years ago

3 0

The answer is 2 I think

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IS IT BETTER OR WORSE TO WORKOUT/EXERCISE IN DARK OR LIGHT COLORED CLOTHING?

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Dark clothing

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How does a heat affect the chemical reaction?

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Increasing the temperature increases reaction rates because of the disproportionately large increase in the number of high energy collisions. It is only these collisions (possessing at least the activation energy for the reaction) which result in a reaction.

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3 years ago

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The conversation of cyclopropane to propene in the gas phase is a first order reaction with a rate constant of 6.7x10-⁴s-¹. a) i

Rus_ich [418]

Answer: a) The concentration after 8.8min is 0.17 M

b) Time taken for the concentration of cyclopropane to decrease from 0.25M to 0.15M is 687 seconds.

Explanation:

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant

t = age of sample

a = let initial amount of the reactant

a - x = amount left after decay process

a) concentration after 8.8 min:

$8.8\times 60s=\frac{2.303}{6.7\times 10^{-4}s^{-1}}\log\frac{0.25}{a-x}$

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$\frac{0.25}{a-x}=1.41$

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b) for concentration to decrease from 0.25M to 0.15M

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3 years ago

The decomposition of N2O4 into NO2 has Kp = 2. Some N2O4 is placed into an empty container, and the partial pressure of NO2 at e

Sunny_sXe [5.5K]

Answer: Option (B) is the correct answer.

Explanation:

Expression for the given decomposition reaction is as follows.

$N_{2}O_{4} \rightarrow 2NO_{2}$

Let us assume that x concentration of $N_{2}O_{4}$ is present at the initial stage. Therefore, according to the ICE table,

$N_{2}O_{4} \rightarrow 2NO_{2}$

Initial : x 0

Change : - 0.1 $2 \times 0.1$

Equilibrium : (x - 0.1) 0.2

Now, expression for $K_{p}$ of this reaction is as follows.

$K_{p} = \frac{P^{2}_{NO_{2}}}{P_{N_{2}O_{4}}}$

Putting the given values into the above formula as follows.

$K_{p} = \frac{P^{2}_{NO_{2}}}{P_{N_{2}O_{4}}}$

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$2 \times (x - 0.1) = (0.2)^{2}$

x = 0.12

This means that $P_{N_{2}O_{4}}$ = x = 0.12 atm.

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3 years ago

What is the maximum number of electrons that any 'p' sublevel can hold? 2 electrons 6 electrons 8 electrons 10 electrons

Varvara68 [4.7K]

6 electrons... 's' can hold 2..... 'd' can hold 10 and 'f' can hold 14

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