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svet-max [94.6K]
3 years ago
5

Help pleaseeeeeeeee!

Chemistry
1 answer:
VMariaS [17]3 years ago
3 0
Middle one because otherwise the substance wouldn’t be a compound
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PLEASEEEE HELP WILL MARK BRAINLIEST!!!
nevsk [136]

Answer:

C. One mole of water was produced from this reaction.

Explanation:

  • From the balanced equation:

<em>2H₂ + O₂ → 2H₂O,</em>

It is clear that 2 mol of H₂ react with 1 mol of O₂ to produce 2 mol of H₂O.

  • So, if one mole of hydrogen was used in this reaction:

1/2 mol of O₂ was used in the reaction, and

1 mol of water was produced from this reaction.

  • So, the correct statement is:

<em>C. One mole of water was produced from this reaction. </em>

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3 years ago
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One group of students did an experiment to study the movement of ocean water. The steps of the experiment are listed below.
Mandarinka [93]
There was no equipment to create temperature difference in the water
hope this helps and can i get a brainly?
btw i make deals, if thi is wrong i own you ten questions you can ask me on my pf for free and i'll do it! 
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3 years ago
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After our solar system began to form, dust and gas combined into small bodies that formed the planets. What are these small bodi
saul85 [17]

Answer:

Planetesimal

Explanation:

According to Nebular Theory, the Solar system was formed from the Solar Nebula about 4.6 billion years ago. Nebula is a molecular cloud composed of dust and gases. Majority of the mass accreted to form a core which gradually formed the Sun. The remaining mass of the disk surrounding the core accreted into small bodies known as Planetesimal which formed the planets.

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A mixture of water and graphite is heated to 600 K in a 1 L container. When the system comes to equilibrium it contains 0.17 mol
Kryger [21]

Answer:

0.44 moles

Explanation:

Given that :

A mixture of water and graphite is heated to 600 K in a 1 L container. When the system comes to equilibrium it contains 0.17 mol of H2, 0.17 mol of CO, 0.74 mol of H2O, and some graphite.

The equilibrium constant K_c=  \dfrac{[CO][H_2]}{[H_2O]}

The equilibrium constant  K_c=  \dfrac{(0.17 )(0.17)}{0.74}

The equilibrium constant K_c=  0.03905

Some O2 is added to the system and a spark is applied so that the H2 reacts completely with the O2.

The equation for the reaction is :

H_2 + \dfrac{1}{2}O_2 \to H_2O \\ \\ 0.17 \ \ \ \ \  \ \ \ \ \to0.17

Total mole of water now = 0.74+0.17

Total mole of water now = 0.91 moles

Again:

K_c=  \dfrac{[CO][H_2]}{[H_2O]}

0.03905 =  \dfrac{[0.17+x][x]}{[0.91 -x]}

0.03905(0.91 -x) = (0.17 +x)(x)

0.0355355 - 0.03905x = 0.17x + x²

0.0355355 +0.13095 x -x²

x² - 0.13095 x - 0.0355355 = 0

By using quadratic formula

x = 0.265  or   x = -0.134

Going by the value with the positive integer; x = 0.265 moles

Total moles of CO in the flask when the system returns to equilibrium is :

= 0.17 + x

= 0.17 + 0.265

= 0.435 moles

=0.44 moles (to two significant figures)

3 0
3 years ago
One type of bacteria reproduces once every 60 minutes. If there are 2 bacterial cells to begin with, then after 4 hours there wi
dlinn [17]
Answer:
Solving by the method of exponential growth.
bacteria = 2
after one hr = 2² = 4
after 2nd hr = 2³ = 8
after 3rd hr = 2⁴ = 16
after 4th hr = 2⁵ = 32
7 0
3 years ago
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