Question

The Pythagorean theorem is a² + b² = c². Solve for b. b=±c+a−−−−√ b=±c2−a2−−−−−−√ b=±c2+a2−−−−−−√ b=±c−a−−−−√

Answer 1

$a^{2} +b^{2} =c^{2}$

As we have to solve for b, it means we have to isolate b

So first of all subtract $a^{2}$ from both sides

So we get

$b^{2} =c^{2} -a^{2}$

Now we need b , but its b^2 , so we can take square root on both sides.

taking square roots on both sides

$b= +- \sqrt{c^2 -a^2}$

Hence option B is correct